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Ira Lisetskai [31]
3 years ago
8

6 is 4% of what number?

Mathematics
1 answer:
Ahat [919]3 years ago
8 0

Answer:

150

Step-by-step explanation:

since 4 percent would have to be multiplied by 25 to get 100 you have to multiply 6 by 25. This comes out to 150. You can even check this by doing 150 times 0.04 which is 6 so we are correct!

You might be interested in
A machine for baking hay produces cylindrical bales that are 6 feet in diameter and 5 1/3 feet in height. Which is closest to th
GaryK [48]
We know that
diameter=6 ft----------> r=6/2------> r=3 ft
h=5 1/3 ft------> (5*3+1)/3-----> 16/3 ft
[volume of a cylindrical bales]=pi*r²*h----> pi*3²*16/3---> 150.72 cm³

the answer is the option
<span>B 151 cm</span>³
5 0
3 years ago
What is 12a equal to if 4a plus 6b = 10 and 2a-4b=12?
hram777 [196]
12a=x
4a+6b=10
2a+3b=5
2a-4b=12
a-2b=6
2a+3b+1=a-2b
a+5b+1=0
a=-1-5b

2(-1-5b)+3b=5
-2-10b+3b=5
-2-7b=5
-7b=7
7b=-7
b=-1

-1-5*-1=a
-1+5=a
4=a

4*12=48
12a=48

Hope this helps :)
3 0
3 years ago
Read 2 more answers
Find the value of x.
AnnyKZ [126]

Answer: 69

Step-by-step explanation: a triangle adds up to 180 degrees. It is an isosceles triangle (2 sides are the same angle) 180-42=138 then do 138/2=69

5 0
3 years ago
What is the value of y in the equation 4y – 2(1 – y) = –44?
LekaFEV [45]
Y=-7 use distributive property add like terms 


8 0
4 years ago
According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati
Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0
3 years ago
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