Hi there!

To find the indefinite integral, we must integrate by parts.
Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":
u = 4x
du = 4
dv = cos(2 - 3x)
v = 1/3sin(2 - 3x)
Write into the format:
∫udv = uv - ∫vdu
Thus, utilize the solved for expressions above:
4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx
Simplify:
-4x/3 sin(2 - 3x) - ∫ 4/3sin(2 - 3x)dx
Integrate the integral:
∫4/3(sin(2 - 3x)dx
u = 2 - 3x
du = -3dx ⇒ -1/3du = dx
-1/3∫ 4/3(sin(2 - 3x)dx ⇒ -4/9cos(2 - 3x) + C
Combine:

Your answer is 7.
I subtracted 5 from 12 to find the missing number for KL that is 7.
Therefore, your answer is 7
Answer:
translate the graph 5 units left and down 2 units
Step-by-step explanation:
To translate the function f(x) by an amount h units right and k units up, make the transformation ...
g(x) = f(x -h) +k
Comparing this to your equation,
g(x) = f(x +5) -2
we see that the translation is h = -5, k = -2.
The graph of f(x) is translated 5 units left and 2 units down to make the graph of g(x).