X2+5x+y2-y=-2
X2+2*5x2+(5/2)^2-(5/2)^2+y2-2*y/2+(1/2)^2-(1/2)^2=-2
(x+5/2)^2+(y-1/2)^2-13/2=-2
(x+5/2)^2+(y-1/2)^2=9/2
So centre =(-5/2,1/2)
Radius=(9/2)^(1/2)
In the given equation, as the value of <em>y</em> increase, the value of <em>x</em> also
increases.
- Yes, 4·y = 16·x is a direct variation
Reasons:
A direct variation is a relationship that exists between two variables. It is
also known as a direct proportion which can be expressed as; y = k·x
Where <em>k</em> is a number
The given equation is 4·y = 16·x
Dividing both sides by 4 gives;

Which gives;
y = 4·x
Comparing the above equation with the equation for a direct variation gives;
y = 4·x
y = k·x
Therefore;
k = 4
The equation, y = 4·x, and therefore, the equation from which it is derived, 4·y = 16·x, is a direct variation.
Learn more about direct variation here:
brainly.com/question/6499629
Answer:
x = 159; y = 140
Step-by-step explanation:
a = 40
a + y = 180
y = 180 - 40
y = 140
b = 61
b = (180 - x) + a
61 = 180 - x + 40
x = 159
2 angles are complementary if the sum of their measures is 90°.
For example if m(P) = 41° and m(Q)=49°, then P and Q are complementary.
Thus A and B are complementary means that m(A)=m(B)=90°:
(3x+5°) + (2x-15°) =90°
5x-10°=90°
5x=100°
x=20°
Thus
m(A)=3x+5°=3* 20°+5°=60°+5°=65°
m(B)=2x-15°=2*20°-15°=40°-15°=25°