Answer:
19, 21, 23
Step-by-step explanation:
Let the first odd number be n.
Then the second, consecutive odd number will be (n+2).
And the third will be (n+4).
We know that they sum to 63. Hence, we can write the following equation:

Solve for n. Combine like terms:

Subtract 6 from both sides:

Divide both sides by 3:

Hence, the first odd number is 19.
Therefore, our sequence is: 19, 21, 23.
Note: If we get an even or non-integer value for our n, then there are no three consecutive odd integers that exists that sum to 63.
Answer:
1 3/7 quarts should be drained off and replaced with pure antifreeze.
1 3/7 ≈ 1.4286
Current amount of antifreeze in quarts is -
30/ 100 × 10 = 3
40% ---> 4 quarts
Let the amount drained of and replaced with antifreeze be x-
The amount left after draining off is 10 − x.
The amount of antifreeze is 30/ 100 (10−x).
30/100(10-x)+x=4
3-3/10x+x=4
3+x(1-3/10)=4
x=1*10/7=1 3/7 quarts
check;
10- 1 3/7 = 8 4/7
=(30/100*8 4/7)+1 3/7
=(3/10 * 60/7) + 10/7
=3*6/7 + 10/7
=28/7
=4
4 liters of pure antifreeze is mixed into 10 quarts.
-1/4 is not = -1 / 1/4 ( its = -4) so its neither .
Answer:
12
Step-by-step explanation: