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aalyn [17]
3 years ago
15

One third the sum of two numbers is 23.If one of the numbers is 29.3,what is the other number​

Mathematics
1 answer:
Mariana [72]3 years ago
6 0
39.7 I think I’m not sure
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Select the correct solution set.<br> X+17 5 -3<br> {XIX2-20)<br> {XIXS-20)<br> [xl xs 14
gtnhenbr [62]

Answer:

x≤-20

Step-by-step explanation:

x+ 17≤-3

Subtract 17 from each side

x+ 17 -17≤-3-17

x≤-20

3 0
3 years ago
A rectangle is shown. 2 right triangles sit on the top of the rectangle. The sides of the rectangle are congruent with 2 sides o
Salsk061 [2.6K]

Answer:3x2

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
A parallelogram has sides 10m and 12m and an angle of 45°. Find the distance between the 12m-sides.
stich3 [128]

Answer:

The distance between 12m-sides is 5\sqrt{2}m.

Step-by-step explanation:

It is given that the parallelogram has sides 10m and 12m and an angle of 45°.

Draw an altitude from one 12m side to another 12 m side as shown in below figure.

The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.

Since angle C is acute angle therefore it must be 45 degree.

\sin\theta=\frac{perpendicular}{hypotenuse}

\sin C=\frac{BE}{BC}

\sin(45^{\circ})=\frac{d}{10}

\frac{1}{\sqrt{2}}=\frac{d}{10}

\frac{10}{\sqrt{2}}=d

\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=d

\frac{10\sqrt{2}}{2}=d

5\sqrt{2}=d

Therefore the distance between 12m-sides is 5\sqrt{2}m.

4 0
3 years ago
The slope of a line passing through points (1, 2) and (1, 3) is equal to:<br><br><br> helpp
Grace [21]
I would help but what are you answer choices?
5 0
3 years ago
What is the area of this figure? <br><br> ____ units²
skad [1K]
To solve the problem we could separate the figure into three parts. First figure is a triangle, second figure is a rectangle, third figure is a triangle. See image attached.

Solve each area of the figures
First figure, a triangle that have 7 units long of the base, and 2 units long of the height.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the first figure is 7 units²

Second figure is a rectangle, the length of the rectangle is 7 units, the width of the rectangle is 4 units.
a = l × w
a = 7 × 4
a = 28
The area of the second figure is 28 units²

Third figure is a triangle, the base is 7 units long and the height is 2 units long.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the third figure is 7 units²

The area of the three figures
area = first figure area + second figure area + third figure area
area = 7 + 28 + 7
area = 42
The total area of the figures is 42 units²

5 0
3 years ago
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