Answer:
0.3721 or 37.21%
Step-by-step explanation:
P(I) = 0.60; P(II) = 0.40;
P(not defective I) = 0.90; P(not defective II) = 0.80
The probability that the phone came from factory II, given that is not defective, is determined by the probability of a phone from factory II not being defective divided by the probability of a phone not being defective.

The probability is 0.3721 or 37.21%.
Answer:
0.9332
Step-by-step explanation:
Answer:
3,400
Step-by-step explanation
Move the decimal place 3 times to the right (the number of zero's is how many places you go)
<span>
<u><em>Answer:</em></u>g = 3
<u><em>Explanation:</em></u>To solve for g, we will need to isolate the g on one side of the equation.
<u>This can be done as follows:</u>
</span>

<span>
<u>1- multiply all terms by 14 to get rid of the fraction:</u>
4g - 6 - g = 3
<u>2- Combine like terms:</u>
4g - g = 3 + 6
3g = 9
<u>3- Isolate the g:</u>
</span>

<span>
g = 3
Hope this helps :)</span>