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Oduvanchick [21]

4 years ago

5

A rectangular container has a base that is 12 inches long and 8 inches wide. The container is filled with water to a height of 6

inches. If all the water is poured into a second container with a square base, it will rise to a height of 16 inches. What is the length of one edge of the square base of the second container?

1 answer:

valina [46]4 years ago

7 0

Answer: the length of one edge of the square base of the second container is 6 inches.

Step-by-step explanation:

The formula for determining the volume of a rectangular container is expressed as

Volume = length × width × height

Considering the first container,

Length = 12 inches

Width = 8 inches

Height to which the water is filled is 6 inches.

Therefore, volume of water in the container is

12 × 8 × 6 = 576 inches³

Considering the second container,

Height of water = 16 inches

Let L represent the length of the square base. Then the area of the square base is L²

Volume of water would be 16L²

Since the water in the first container was poured into the second container, then

16L² = 576

L² = 576/16 = 36

L = √36

L = 6 inches

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Use the diagram to answer each part of the question. The image is not drawn to scale.

Mnenie [13.5K]

The height of the tree and the building are 7.6 m and 28.6 m respectively.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Two triangles are similar if they have the same shape and the ratio of their corresponding sides are in the same proportion.

Triangle BGD, CHD and AFD are similar triangles.

CH = 1.6, DH = 8, GH = 30, GF = 105

FH = GF + GH = 105 + 30 = 135

FD = FH + DH = 135 + 8 = 143; GD = 30 + 8 = 38

Hence, using similar triangles:

BG/CH = GD / DH

BG / 1.6 = 38/8

BG = 7.6 m

Also:

building/CH = DF / DH

building / 1.6 = 143/8

building = 28.6 m

The height of the tree and the building are 7.6 m and 28.6 m respectively.

Find out more on equation at: brainly.com/question/2972832

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5 0

2 years ago

3. Which graph best represents the solution to the following system? (1 point)<br> (5x – 2y <10

Step2247 [10]

Answer:

The graph in the attached figure

Step-by-step explanation:

The complete question is

Which graph best represents the solution to the following system?

5x - 2y < (less than or equal to) 10

x + y < 5

we have

$5x-2y\leq 10$ ----> inequality A

isolate the variable y

Adds 2y both sides

$5x \leq 10+2y$

Subtract 10 both sides

$5x-10 \leq 2y$

Divide by 2 both sides

$2.5x-5 \leq y$

Rewrite

$y \geq 2.5x-5$

The solution of the inequality A is the shaded area above the solid line

The equation of the solid line is $y=2.5x-5$

The slope of the solid line is positive $m=2.5$

The y-intercept of the solid line is (0,-5)

The x-intercept of the solid line is (2,0)

$x+y < 5$ -----> inequality B

Isolate the variable y

Subtract x both sides

$y < -x+5$

The solution of the inequality B is the shaded area below the dashed line

The equation of the dashed line is $y=-x+5$

The slope of the dashed line is negative $m=-1$

The y-intercept of the dashed line is (0,5)

The x-intercept of the dashed line is (5,0)

using a graphing tool

The solution of the system of inequalities is the shaded area between the solid line and the dashed line

see the attached figure

7 0

3 years ago

The perimeter of (the distance around) ABCD is 66, and DC is twice as long as CB. How long is AB?

ArbitrLikvidat [17]

Answer:

$AB=22\ units$

Step-by-step explanation:

we know that

In this problem ABCD is a rectangle

so

DC=AB

BC=AD

Let

BC ---> the length of rectangle

DC ---> the width of rectangle

we know that

The perimeter of rectangle is equal to

$P=2(BC+DC)$

we have

$P=66\ units$

so

$66=2(BC+DC)$

simplify

$33=BC+DC$ ----> equation A

$DC=2BC$ ----> equation B

substitute equation B in equation A

$33=BC+2BC$

Solve for BC

Combine like terms

$33=3BC$

Divide by 3 both sides

$BC=11\ units$

<em>Find the value of DC</em>

$DC=2BC$ ----> $DC=2(11)=22\ units$

Remember that

DC=AB

therefore

$AB=22\ units$

3 0

3 years ago

Find the length of AX. Please!!

valentinak56 [21]

Answer:

hope this helps.. look at it this way it should help!!

Step-by-step explanation:

Considered as an ideal camping axe, the Boy’s Axe (also called the ¾ Axe) usually has a length of 28 inches, ¾ of 36 inches being 27 inches or roughly 700 millimeters. Finally, the Scout Axe has an average handle length of 18-20 inches or 450-500 millimeters.

6 0

3 years ago

Convert the angle \theta=\dfrac{8\pi}{9}θ=

Olegator [25]

Answer:

160°

Step-by-step explanation:

-Given the angle in radians as $\theta=\dfrac{8\pi}{9}\ rad$

-We know that $1 \ rad=\frac{180}{\pi}\textdegree$

-Let our angle theta be X

#We therefore equate and cross multiply:

$1\ rad=\frac{180}{\pi}\\\\\frac{8\pi}{9}=x\\\\\therefore X=\frac{180}{\pi}\times \frac{8\pi}{9}\\\\=160\textdegree$

Hence, angle θ is 160°

8 0

3 years ago