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BlackZzzverrR [31]
3 years ago
9

I need help rn please​

Mathematics
2 answers:
neonofarm [45]3 years ago
6 0

Answer:

3/1 I am not absolutely sure though...

timofeeve [1]3 years ago
6 0

Answer:

3/1

Step-by-step explanation:

Rise over run

Find a place where the line meets a cross section (corner of a box, where two graph lines meet) on the graph

I'm looking at -3, -3

Then we go straight up the graph on -3 until the line meets an other one of those cross sections. It does this at 0, -2. Count or add up how far we moved.

We're going to count over how far that is from where we are from the last step. You should have made a little triangle with the two graph lines and our blue line if you were to draw what we just did.

We moved up 3 and over 1 to get from the first cross section to the second. You can do this at any cross section on the graph that the blue line touches.

3/1

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(2x+1)(x+5)<br> 6x-4xy<br> 16x^2-25
timofeeve [1]
-32xy-25 try dat anyways have a nice dayyyy byeeeee
8 0
2 years ago
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Help...this is due in a few hours
Mrrafil [7]

Answer:

21

Step-by-step explanation:

14+7=21.

You do this to allow you to get that outcome, because you know 7*7=49.

Therefore 21-14=7

7*-7=49

6 0
3 years ago
I need this answer I Need Help
Yakvenalex [24]

Answer: ok, the area is 3960, the perimeter is 268, and type is rectangle

Step-by-step explanation:

8 0
3 years ago
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Evaluate h(x)=4x-2 find h(x+2)
sleet_krkn [62]
H(x)=4x-2

In the equation

h(x+2) we substitute x for x+2 ....

h(x+2)=4x+2-2
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6 0
3 years ago
Read 2 more answers
1. If Triangle ADC is the image of Triangle AEB, which is the proper term for point A?
m_a_m_a [10]

Answer:  The correct options are (1) (a) Centre of dilation and (2) (a) 2.

Step-by-step explanation:  The solutions are as follows:

(1) Given that the triangle AEB is dilated to form triangle ADC. We are to select the correct term for point A.

We see that the point A is a fixed point in the plane about which ΔAEB is dilated to form ΔADC.

Also, we know that a fixed point in the plane about which the figure is dilated is called the centre of dilation. So, A is the centre of dilation.

Thus, (a) centre of dilation is the correct option.

(2) The length of the line segment with end-points (2, -1) and (4, 2) is given by

l_1=\sqrt{(4-2)^2+(2+1)^2}=\sqrt{4+9}=\sqrt{13},

and the length of the dilated image segment with end-points (4, -2) and (8, 4) is given by

l_2=\sqrt{(8-4)^2+(4+2)^2}=\sqrt{16+36}=\sqrt{52}=2\sqrt{13}.

Therefore, the scale factor will be

S-c=\dfrac{\textup{length of the dilated segemnt}}{\textup{length of the original segment}}=\dfrac{2\sqrt{13}}{\sqrt{13}}=2.

Thus, the correct option is (a) 2.

4 0
3 years ago
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