Explanation
We must the tangent line at x = 3 of the function:
The tangent line is given by:
Where:
• m is the slope of the tangent line of f(x) at x = h,
,
• k = f(h) is the value of the function at x = h.
In this case, we have h = 3.
1) First, we compute the derivative of f(x):
2) By evaluating the result of f'(x) at x = h = 3, we get:
3) The value of k is:
4) Replacing the values of m, h and k in the general equation of the tangent line, we get:
Plotting the function f(x) and the tangent line we verify that our result is correct:
Answer
The equation of the tangent line to f(x) and x = 3 is:
B. 2 I believe that’s right
Answer:
<h3>The answer is option D.</h3>
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
Slope of the line using points ( 5 , - 1) and
( - 5 , 2) is
m = 2+1/ -5-5 = - 3 / 10
Equation of the line using point ( 5 , - 1) is
y + 1 = -3/10(x - 5)
y = -3/10x + 3/2 - 1
The final answer is
<h3>y = - 3/10x + 1/2</h3>
Hope this helps you.
Answer:
sec (x)
Step-by-step explanation:
sec (x) tan (x) cos (x) csc (x) =
We know sec = 1/ cos
Tan = sin/cos
csc = 1/sin
Replacing into the expression
1/ cos (x) * sin(x)/ cos (x) * cos (x) * 1 / sin(x)
Canceling like terms
1/ cos (x)
sec(x)
I'm guessing that x2 is an x to the power of 2, so u can rewrite that as:
x^2 - x - 4
from there you can use completing the square, quadratic function, or factoring.
If the x2 is supposed to be 2x then it would just be as follows:
x - 4
