Find the area of the region bounded by the line y=3x−6 and line y=−2x+8. a) the x-axis.

Mathematics

1 answer:

Shtirlitz [24]2 years ago

5 0

I think this is what you mean

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Scientific Notation in 0.025

horrorfan [7]

2.5 x 10⁻²
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3 years ago

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GaryK [48]

Answer:

$f'(x) = -28 \ at \ x = 2$

Step-by-step explanation:

$f'(2) = \lim_{h \to 0}\frac{f(2+h)) -f(2)}{h} \\\\f(2+h) = 1 - 7(2+h)^2 = 1 - 7(4 +h^2 +4h) = 1 - 28 - 7h^2 - 28h = - 7h^2 -28h - 27\\\\f(2) = 1 - 7(2^2) = 1 - 28 = -27\\\\f(2+h) - f(2) = -7h^2 - 28h - 27 - (-27) = -7h^2 -28h -27 + 27 = -7h^2 -28h\\\\f'(2) = \lim_{h \to 0}\frac{-7h^2 - 28h}{h} \\\\$

$= \lim_{h \to 0} \frac{h(-7h -28)}{h}\\\\= \lim_{h \to 0} (-7h -28)}\\\\= -7 (0) - 28\\\\= -28$

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2 years ago

Use the order of operations to evaluate the expression.

Lera25 [3.4K]

Answer:

the answer is 12

Step-by-step explanation

first you got to divide the 12 and the 3 which is 4

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Step-by-step explanation:

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