Answer:
It would be 5.1942486
Step-by-step explanation:
Becuase the 0 is after the 6 the 6 stays as it is and there is no need to round up or down
Answer:
a. 2^3
b. 3^4
c. 4^3 × 5^2
d. 9^4 × 7^2
Step-by-step explanation:
The following equations are given
a. 2 × 2× 2
b. 3 × 3 × 3 × 3
c. 4 × 4 × 4 × 5 × 5
d. 9 × 7 × 9 × 9 × 7 × 9
We need to find the index notation for the above equations
a. 2^3
b. 3^4
c. 4^3 × 5^2
d. 9^4 × 7^2
In this way it should be done
The same would be relevant
Given the equation:
We will use the following rule to find the solution to the equation:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
From the given equation: a = 6, b = 7, c = 2
So,
![\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=\frac{-7\pm1}{12} \\ x=\frac{-7-1}{12}=-\frac{8}{12}=-\frac{2}{3} \\ or,x=\frac{-7+1}{12}=-\frac{6}{12}=-\frac{1}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B7%5E2-4%5Ccdot6%5Ccdot2%7D%7D%7B2%5Ccdot6%7D%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B1%7D%7D%7B12%7D%3D%5Cfrac%7B-7%5Cpm1%7D%7B12%7D%20%5C%5C%20x%3D%5Cfrac%7B-7-1%7D%7B12%7D%3D-%5Cfrac%7B8%7D%7B12%7D%3D-%5Cfrac%7B2%7D%7B3%7D%20%5C%5C%20or%2Cx%3D%5Cfrac%7B-7%2B1%7D%7B12%7D%3D-%5Cfrac%7B6%7D%7B12%7D%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cend%7Bgathered%7D)
So, the answer will be option B) x = -1/2, -2/3
Answer:
x < 3
Step-by-step explanation:
Solve it like a normal equation
Isolate the variable along with its constant
9x - 6 + 6< 21 + 6
9x < 27
Isolate the variable its self
9x/9 < 27/9
x < 3
<h2>
REMEMBER : ONLY FLIP THE INEQUALITY SIGN WHEN <u>
MULTIPLYING</u>
OR <u>
DIVIDING</u>
BY A <u>
NEGATIVE NUMBER</u></h2>
