<span>First of all to calculate the distance between two points we can use distance formula
d=Square Root [(x2-x1)^2 + (y2-y1)^2]
Now substitute the given points p(x1,y1) and q(x2,y2)in above distance formula
The values are X2=3, X1=8and Y2=8and Y1=2.
After Substituting the values
d=Square Root[(-5)^2+(6)^2]
d=Square Root(25+36]
d=Square Root[61]
d=7.8
7.8 is the distance between points P(8, 2) and Q(3, 8) to the nearest tenth.</span>
Answer:
16 millimeters
Step-by-step explanation:
- Length of the Triangular Prism=4 millimeters
- Base Length of One Triangular Face=13 millimeters.
- Volume of the Prism =416 cubic millimeters.
Now:
Volume of a Prism=Base Area X Prism Length
Since we have a triangular base:
Volume of the Prism=(0.5 X Base X Height) X Prism Length
Substituting the given values, we obtain:
416=(0.5 X 13 X Height) X 4
416=26 X Height
Divide both sides by 26
Height of its triangular face=16 millimeters
Answer:
5/8
5/8
Step-by-step explanation:
Answer:
1.f(x)=2x-5
i will take the set {-2,-1,0,1,2}
f(-2)=2(-2)-5
=-4-5
=-9
f(-1)=2(-1)-5
=-2-5
=-7
f(0)=2(0)-5
=-5
f(1)=2(1)-5
=-3
f(2)=2(2)-5
=-1
so the coordinates of the function is {-9,-7,-5,-3,-1}
2.f(x)=-3x+6
i will the take the set {-2,-1,0,1,2} too
f(-2)=-3(-2)+6=6+6=12
f(-1)=-3(-1)+6=3+6=9
f(0)=-3(0)+6=6
f(1)=-3(1)+6=-3+6=3
f(2)=-3(2)+6=-6+6=0
{12,9,6,3,0}
3.f(x)=2/3.x+4
{-2,-1,0,1,2}
f(-2)=2/3(-2)+4=-4/3+4=(-4+12)/3=8/3
f(-1)=2/3(-1)+4=-2/3+4=(-2+12)/3=10/3
f(0)=2/3(0)+4=4
f(1)=2/3(1)+4=2/3+4=(2+12)/3=14/3
f(2)=2/3(2)+4=4/3+4=(4+12)/3=16/3
{8/3,10/3,4,14/3,16/3}
you're can graph those coordinates
actually you can take other coordinates...
CMIIW
,
Number 2 is $4 not $.40 and 3 is 10% OFF not added to. Those are all I had time to check but 1 is right
