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Doss [256]
3 years ago
12

Determine whether the sides given would form an acute,obtuse, or right triangle 7,7,12

Mathematics
1 answer:
Yuliya22 [10]3 years ago
5 0

Its a obtuse angle since 7^2 is 49 7^2 is 49 and 12^2 is 144
144 is bigger than 90 so its obtuse triangle

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Part A: 180 = 4m + b B = 180 + 4m 325 = 9m + b 325 - 180 = 9m - 4m 5m = 145 m = 29 b = 180 + 4(29) = 64 y = 29x + 64
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5 0
3 years ago
One angle of a right triangle measures 65°. What is the measure of the other acute angle?
kvasek [131]

answer:

25°

explanation:

triangle total: 180°

right angle: 90°

90 + 65 = 155

180 - 155 = 25

hope this helped!

6 0
3 years ago
Evaluate the expression when x=7 and y=-3. 5y2-x
DIA [1.3K]

Answer:

-37

Step-by-step explanation:

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3 years ago
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6 0
3 years ago
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The hypotenuse of a right triangle is 37 units long. Find the other two sides if the perimeter of the triangle is 84 units. Sepa
taurus [48]

Answer:

The lengths of the legs are 12 and 35 units

Step-by-step explanation:

Let c represent the hypotenuse and a and b represent the legs.  Then the Pythagorean Theorem requires that a^2 + b^2 = c^2 = 37^2 = Hypotenuse^2

Also:  a + b + c = Perimeter = 84 units.  

Since c = 37 units, a + b + 37 units = 84 units, or a + b = 47 units, or a = 47 - b.

Then a^2 + b^2 = 37^2 becomes (47 - b)^2 + b^2 = 37^2, or 1369.  Therefore:

2209 - 94b + b^2 + b^2 = 1369.

Simplifying by combining like terms, we get:  

840 - 94b + 2b^2 = 0, which is a quadratic equation in standard form.

Reducing all terms by division by 2, we get:

420 - 47b + b^2 = 0.  Here the coefficients are a = 1, b = -47 and c = 420.

The discriminant is therefore b^2 - 4ac, or 529, whose square root is ± 23.

Then the b values of this quadratic in b are

      47 ± 23

b = -------------- , so that b is either 35 or 12

             2

and then side a has length a = 47 - b = 12  or  35.

Thus, a = 12 and b = 35, and c is given:  37.

Check:  Is 12^2 + 35^2 = 37^2 true?  Is 144 + 1225 = 1369?  YES

The lengths of the legs are 12 and 35 units.

7 0
3 years ago
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