The oldest age pat could be ia 10.10 times 2 equals 20.20 plus 5 is 25 .
9514 1404 393
Answer:
- soccer: $50.31
- hockey: $57.78
Step-by-step explanation:
Let s represent the FCI for soccer. The given values tell us ...
s + (s +7.47) = 108.09
2s = 100.62 . . . . . . . . . . subtract 7.47
s = 50.31
s+7.47 = 57.78
The FCI for soccer was $50.31; the FCI for hockey was $57.78.
Answer:
10657.5
Step-by-step explanation:
<h2>
Long way that is unnecessarily long</h2>
We can start by finding the area of the larger triangle. Using the Pythagorean theorem, we can say that 251²-105²=the bottom side², and 251²-105²=51976, so the bottom side of the larger triangle is √51976 , or approximately 228. Then, the area of the larger triangle is √51976 * 105/2 = 11969 (approximately). Then, the area of the smallest triangle (the largest triangle - the one that we're trying to find the area of) is 105*(√51976-203)/2 = approximately 1312. Then, subtracting that from the total area, we get (√51976 * 105 - 105*(√51976-203))/2 = 105*203/2 = 10657.5
<h2>Short way</h2>
ALTERNATIVELY, upon further review, we can just see that the height is 105 and the base is 203, so we multiply those two and divide by 2, as is the formula for the area of a triangle, to get 10657.5
Answer:
The height of the pole is 167 m
Step-by-step explanation:
The given parameters are;
Increase in the length of the shadow = 90 m
Initial angle of elevation of the Sun = 58°
Final angle of elevation of the Sun = 36°
We have a triangle formed by the change in the length of the shadow and the rays from the two angle of elevation to the top of the pole giving an angle 22° opposite to the increase in the length of the shadow
We have by sin rule;
90/(sin (22°) = (Initial ray from the top of the pole to the end of the shadow's length)/(sin(122°)
Let the initial ray from the top of the pole to the end of the shadow's length = l₁
90/(sin (22°) = l₁/(sin(122°)
l₁ = 90/(sin (22°) ×(sin(122°) = 283.3 m
Therefore;
The height of the pole = 283.3 m × sin(36°) = 166.52 m
The height of the pole= 167 m to three significant figures.
