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mojhsa [17]
3 years ago
9

Can you guys help me please

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

a = 42

Step-by-step explanation:

2a + 16 + 80 = 2a + 96

2a + 96 = 180

2a = 84

a = 42

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By graphing the system of constraints, find the values o f x and y that minimize the objective function.
svet-max [94.6K]

Graph the inequalities to find the vertices of the shaded region: (2, 3) and (8, 0).

Now, evaluate the the function C = x + 3y at those vertices to find the minimum value.

C = x + 3y at (2, 3)  ⇒  C = (2) + 3(3)   ⇒  C = 2 + 9   ⇒   C = 11

C = x + 3y at (8, 0)  ⇒  C = (8) + 3(0)   ⇒  C = 8 + 0   ⇒   C = 8

The minimum value occurs at (8, 0) with a minimum of C = 8

Answer: A

5 0
3 years ago
Read 2 more answers
Find the quotient 4/12 divided by 4/12
Natali5045456 [20]

Answer:

1

Step-by-step explanation:

Keep-Change-Flip

4/12 (keep) × (change) 12/4 (flip)

4/12 × 12/4

4 × 12 = 48

12 × 4 = 48

48/48 = 1

3 0
3 years ago
Read 2 more answers
Also need help with this problem too if anyone can help
aleksandrvk [35]

Answer:

A=24 sq ft

P=20 ft

Step-by-step explanation:

To make this easier, separate the triangle and the rectangle. To find the area of the triangle multiply the bases and the height and then divide the answer by. So,

(6x4)/2

(24)/2

A=12

The base of the triangle is the same as the base on the rectangle. To get the perimeter, add the 3 side values up.

5+5+6

P=16

For the rectangle, to get the area, just multiply the base value and the height value. So,

(6x2)

A=12

To get the perimeter, add all the side values up. So,

6+6+2+2

P=12

Add the 5 sides of the pentagon up for the perimeter.

5+5+2+2+6

P=20

And finally, add the area of the triangle and the rectangle to get the area of the pentagon.

12+12

A=24

4 0
3 years ago
Find the vertical asymptote(s) of f of x equals quantity 4 x squared plus 3x plus 6 end quantity over quantity x squared minus 3
siniylev [52]

The vertical asympototes of f(x) are  at x = -6 and x = 6

Step-by-step explanation:

To find the vertical asymptote(s) of a rational function,

  • Equate the denominator by 0
  • Solve it for x
  • If x = a, then the vertical asymptote is at x = a

∵ f(x)=\frac{4x^{2}+3x+6}{x^{2}-36}

- Equate the denominator x² - 36 by 0

∵ x² - 36 = 0

- Add 36 to both sides

∴ x² = 36

- Take √ for both sides

∴ x = ± 6

∴ There are vertical asymptotes at x = -6 and x = 6

The vertical asympototes of f(x) are  at x = -6 and x = 6

Learn more:

You can learn more about the asymptotes in brainly.com/question/6459599

#LearnwithBrainly

4 0
3 years ago
Evaluate (16+a)+ 6b divided by 3 when a = 2 and b = 3
yawa3891 [41]

Answer:   24

Step-by-step explanation:

Follow PEMDAS. Parentheses: 16+a, which is 18. There are no exponents so move on to multiplication. 6b. B is equal to 3, and 6x3 is 18. Next, division. 18/3 is 6. Now do addition so add together 18+6 which is 24.

4 0
2 years ago
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