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2 years ago

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A gym membership charges a one-time application fee of $15, plus $32 each month. Which of the following equations could represen

t the total cost, y, for x number of months?
A.y = 32x + 15
B.y = 15x + 32
C.y = 47x
D.15y = 32x

1 answer:

avanturin [10]2 years ago

4 0

Answer:

The answer is A. y =32x + 15

Step-by-step explanation:

The reason behind this is the rate. The amount of money each month is the slope (m). The additional fee would be the b.

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Paul paid $ 25.50 for 3 cups of hot chocolate and cups of tea. The cost of each cup of tea was 2/3 the cost of each cup of hoy c

Allushta [10]

Let the cost of one cup of hot chocolate be = x

Let the cost of one cup of hot tea be = y

Paul paid $ 25.50 for 3 cups of hot chocolate and 4 cups of tea.

Equation becomes = $3x+4y=25.50$ ...(1)

As given, the cost of each cup of tea was 2/3 the cost of each cup of hot chocolate.

$y=\frac{2x}{3}$ .... (2)

Putting the value of y from (2) in (1)

$3x+4(\frac{2x}{3})=25.50$

= $3x+\frac{8x}{3}=25.50$

= $\frac{9x+8x}{3}=25.50$

= $17x=76.5$

x=4.5

$y=\frac{2x}{3}$

= $\frac{2*4.5}{3}$

y =3

Hence each cup of hot chocolate is $4.50

Each cup of tea is $3.

7 0

3 years ago

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

3 years ago

Construct a 98% confidence interval to determine whether there is any difference between the mean drug concentration in tablets

inna [77]

Answer:

Step-by-step explanation:

So, we are given two sites;

Site one: 91.28 , 92.83, 89.35, 91.90 82.85, 94.83, 89.83, 89.00, 84.62, 86.96, 88.32, 91.17, 83.86, 89.74, 92.24, 92.59, 84.21, 89.36, 90.96, 92.85, 89.39, 89.82, 89.91, 92.16, 88.67.

=> The mean = add up all the numbers/ the total numbers (which is 25). = 89.55.

=> The standard deviation = 3.005

SITE TWO: 89.35 86.51 89.04 91.82 93.02 88.32 88.76 89.26 90.36 87.16 91.74 86.12 92.10 83.33 87.61 88.20 92.78 86.35 93.84 91.20 93.44 86.77 83.77 93.19 81.79.

=> The mean= add up all the numbers/ the total numbers (which is 25). = 89.033.

=> Standard deviation = 3.271.

NB: the assumption here is that the variance for both sites are the same.

STEP ONE: DETERMINE THE DEGREE OF FREEDOM AND THE CRITICAL VALUE.

The degree of freedom =( mean of site 1 ) + (mean of site 2) - 2 = (25 + 25) − 2 = 48.

Since the degree of freedom is 48, Recall that the value for alpha given = 0.02. Then, the critical value = 2.407.

STEP TWO: DETERMINE THE STANDARD DEVIATION AND THE STANDARD ERROR FOR BOTH.

Therefore, the standard deviation = √[( 25 - 1) × 3.005^2 + (25 -1) × 3.271^2) ÷ (25 +25 - 2) ] = 3.14.

Also, the standard error = standard deviation × ( √(1/ mean 1 + 1/mean 2) ..

Standard error = 3.14 × [ ✓( 1/25 + 1/25)] = 0.89.

STEP THREE: DETERMINE THE CONFIDENCE INTERVAL.

confidence interval = (89.548 - 89.033 - 2.41 × 0.89, 89.548 - 89.033 + 2.41 × 0.89) = (- 1.62, 2.65).

STEP FOUR: THE HYPOTHESES.

=> THE TWO TAILED TEST.

Jo:μ1 = μ2.

Ja: μ1 ≠ μ2.

Thus, the rejected region is {t : ∣ t ∣ > 2.7}

As critical value = 2.7 for the degree of freedom which is 48 and α=0.01.

If we do the t - test for this,.we will have;

(89.548 - 89.003)÷ ( standard deviation × √ ( 1/25 + 1/25). = 0.58.

So,from our t - value, is less or equals to the critical value, therefore, the null hypothesis is not rejected.

Also, from the p-value table which gives p=0.565. The p- value is greater than or equal to the alpha value(0.01). therefore, the null hypothesis is not rejected.

We are not going to reject the null hypothesis because the information gathered is not enough.

3 0

2 years ago

Sam said the square root of a rational number must be a rational number. Jenna disagreed. She said that it is possible that the

Nat2105 [25]

Jenna is correct. This is because the square root of 2 is an irrational number. And if the number is a prime number, the answer is less likely to have a rational square root.

6 0

3 years ago

Read 2 more answers

the measure of the supplement of an angle is 30 more than twice the measure of the angle. find the measure of the angles

Ierofanga [76]

Triangle= 180 degrees
Angle = 37.5 degrees
Supplement angle = 105 degrees

If you multiply the angle (37.5) by 2 and then add 30, it gives you 105. Then add 37.5 twice to make up the other two angles of the triangle and it gives you 180 total degrees as a triangle should.

7 0

3 years ago