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3 years ago

How many terms are in this expression? s+3u+10=

Mathematics

1 answer:

Stella [2.4K]3 years ago

3 0

There are 3 terms in this expression s, 3u, and 10

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Number 6 and 7 asap please help

netineya [11]

Hello!

We will write and solve this equation below.

x-24=35

Add 24 to both sides.

x=59

4c=28

Divide both sides by 4.

c=7

I hope this helps!

3 0

2 years ago

Read 2 more answers

Please help I will mark Brainly

Alekssandra [29.7K]

Here u go: D. integer, B.Rational and C. real

3 0

3 years ago

The perimeter of the rectangle is 28 units.

kakasveta [241]

Answer:

5 units

Step-by-step explanation:

P= 2 (l + w) = 2 x (9 + 5) = 28

8 0

2 years ago

Find the value of x so that the function has the given value.

nataly862011 [7]

For h(x) = -7x + 10, x =1

For r(x) = 4/5x+ 7 , x = -15

Step-by-step explanation:

in order to find the value of x on which the functions will have given values, we will put the functions equal to the given values

So,

h(x) = -7x + 10; h(x) = 3

$h(x) = -7x+10\\3 = -7x+10\\3-10 = -7x+10-10\\-7 = -7x$

Dividing both sides by -7

$\frac{-7x}{-7} = \frac{-7}{-7}\\x = 1$

r(x) = 4/5x+7; r(x) = -5

$r(x) = \frac{4}{5}x +7\\-5 = \frac{4}{5}x +7\\-5-7 = \frac{4}{5}x\\-12 = \frac{4}{5}x\\x = -12 * \frac{5}{4}\\x = -15$

Keywords: Functions

Learn more about functions at:

#LearnwithBrainly

3 0

3 years ago

g A 5 foot tall man walks at 10 ft/s toward a street light that is 20 ft above the ground. What is the rate of change of the len

vredina [299]

Answer:

$-\frac{10}{3}ft/s$

Step-by-step explanation:

We are given that

Height of man=5 foot

$\frac{dy}{dt}=-10ft/s$

Height of street light=20ft

We have to find the rate of change of the length of his shadow when he is 25 ft form the street light.

ABE and CDE are similar triangle because all right triangles are similar.

$\frac{20}{5}=\frac{x+y}{x}$

$4=\frac{x+y}{x}$

$4x=x+y$

$4x-x=y$

$3x=y$

$3\frac{dx}{dt}=\frac{dy}{dt}$

$\frac{dx}{dt}=\frac{1}{3}(-10)=-\frac{10}{3}ft/s=-\frac{10}{3}ft/s$

Hence, the rate of change of the length of his shadow when he is 25 ft from the street light= $-\frac{10}{3}ft/s$

7 0

2 years ago