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3 years ago

Let f(-x) = 5x – 2 and g(x) = 2x + 3 and find f(x) –

Mathematics

1 answer:

n200080 [17]3 years ago

8 0

Answer:

3x - 5

Step-by-step explanation:

Given that f(x) = 5x - 2 and g(x) = 2x+3

f(x) - g(x) = 5x-2 - (2x+3)

Expand

f(x) - g(x) = 5x - 2 - 2x - 3

Collect like terms

f(x) - g(x) = 5x - 2x -2-3

f(x) - g(x) = 3x - 5

Hence the required answer is 3x - 5

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(X^2+x-6)(2x^2+4x) factor completely

MissTica

Answer:

$2x\left(x-2\right)\left(x+3\right)\left(x+2\right)$

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring $x^2+x-6$ .

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For $ax^2+bx+c$ we need to find u, v > $u\cdot \:v=a\cdot \:c$ and $u+v=b$ which we will group into $\left(ax^2+ux\right)+\left(vx+c\right)$ .

The values we have are... $a=1,\:b=1,\:c=-6$ and $u\cdot v=-6,\:u+v=1$ .

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

$\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow \mathrm{False}$

$\mathrm{Check}\:u=2,\:v=-3: \:u\cdot v=-6,\:u+v=-1 \Rightarrow \mathrm{False}$

$\mathrm{Check}\:u=3,\:v=-2: \:u\cdot v=-6,\:u+v=1 \Rightarrow \mathrm{True}$

$\mathrm{Check}\:u=6,\:v=-1: \:u\cdot v=-6,\:u+v=5 \Rightarrow \mathrm{False}$

Therefore $u=3,\:v=-2$ .

Now we want to $\mathrm{Group\:into\:}\left(ax^2+ux\right)+\left(vx+c\right)$ . Which is $\left(x^2-2x\right)+\left(3x-6\right)$ .

Now we must factor x from $x^2-2x$ .

Lets apply the exponent rule of $a^{b+c}=a^ba^c$ which means $x^2=xx$ .

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of $3x-6$ .

Rewrite 6 as 3 * 2. $3x-3\cdot \:2$ .

Now factor out the common term of 3 > $3\left(x-2\right)$ .

$x\left(x-2\right)+3\left(x-2\right)$ > Factor out the common term of x - 2 > $\left(x-2\right)\left(x+3\right)$ .

Now lets factor $2x^2+4x$ .

Apply the previous exponent rule of $a^{b+c}=a^ba^c$ > $x^2=xx$ > $2xx+4x$ .

Now rewrite 4 as 2 * 2 > $2xx+2\cdot \:2x$ .

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get $2x\left(x-2\right)\left(x+3\right)\left(x+2\right)$ .

Hope this helps!

7 0

3 years ago

You can sand frac{4}{9}

Reptile [31]

Answer:

Step-by-step explanation:

2 and 38/45 square yards can be sanded in 3.2 hours.

Step-by-step explanation:

1/2 of an hour is 30 minutes. so 4/9 for every 30 minutes. 1 hour is 8/9. So 3 2/10 would be 3 hours =24/9=2 6/9 and 2/10 would be ( if 5/10 is 30 minutes then 2/10 is 12 minutes.) 8/9 x 1/5 = 8/45. (24 x 5 = 120) 120/45 + 8/45 is 128/45 = 2 38/45

7 0

3 years ago

How do fraction tiles help me subtract unlike fractions?

Leokris [45]

Answer:

Step-by-step explanation:

They let you see how one fraction compares to another for one. Say you had 2/5 and 3/7 it may be tricky to tell which is bigger, but having the tiles will let you see that 3/7 is slightly bigger. And there are many many more complicated examples. So if you know which is bigger you will know subtracting the smaller one will keep it positive, while if you subtract the larger from the smaller one it will be negative.

Also, you can then find equivalent tiles. In the example I gave you would be able to see 2/5 = 14/35 and 3/7 = 15/35. Which are like fractions you can subtract simply.

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Which line has a constant of proportionality between y and x of 5

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Answer:

the answer is A on khan academy

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shepuryov [24]

Answer:

Step-by-step explanation:

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