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lions [1.4K]
2 years ago
14

Im lost.. whats the answer?

Mathematics
2 answers:
Ronch [10]2 years ago
8 0

Answer:

B?

Step-by-step explanation:

antiseptic1488 [7]2 years ago
7 0

Answer: B

Step-by-step explanation:

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plzzz help A model train is on a track 100 cm from its starting point. Turning a switch displaces the train either forward or ba
Ad libitum [116K]

Answer: B.  |x-100| = 25

Explanation:

Draw out a number line. Mark 75, 100 and 125 on the number line as points A, B, and C in that order. Don't worry about the spacing.

The value of x represents where the train is. So if we had say x = 85, then it would be at location 85 on the number line. Writing |x-100| is the distance from x to 100. The absolute value ensures the distance is never negative. We want this distance to be 25 because after traveling 25 cm, the switch is turned, and the train goes the other way.

6 0
3 years ago
Can someone please answer this asap (50 Points)<br> Graph the following piecewise function.
kiruha [24]

answer D for the equation

8 0
3 years ago
Read 2 more answers
If someone could please walk me through on how to answer this.
Elis [28]

To isolate c means to separate it completely on one side of the equals sign.


To isolate variables, you apply opposite operations.


In E = mc², m and c are being multiplied together. To separate them, you divide by the variable you want to get rid of. However, you must do this to both sides of the equation always. Whatever you do to one side of the equation you must do to the other side as well. This is so the equation remains true.


Since we want to isolate c, we'll start by dividing both sides by m.


E = mc²

E/m = mc²/m

E/m = c²  --  The m's cancel as 1


Now we have c squared. The opposite of squaring something is taking its square root. Take the square root of each side.


E/m = c²

√(E/m) = √(c²)

√(E/m) = c  --  Opposite operations cancel each other out


And you've isolated c!


Answer:

c = √(E/m)

3 0
3 years ago
What is the average rate of change for this exponential function for the interval from x=2 to x=4?
mario62 [17]

The equation to calculate the average rate of change is: y/x

y = f(x2) - f(x1)x = x2 - x1

x1: 1 (The smaller x value. It can be any number)x2: 2 (The larger x value. It also can be any number)f(x1): The value when you plug x1 into the function.f(x2): The value when you plug x2 into the function.

If we know this, the variables for this problem are assuming the function is 10(5.5)^x:

x2: 2x1: 1f(x2): 10(5.5)^(2) = 302.5f(x1): 10(5.5)^(1)= 55

This means:y = 302.5  - 55 = 247.5x = 2 - 1 = 1

Remember: the equation for avg rate of change is y/x

So, our average rate of change for the function on the interval [1,2] is 247.5 (y/x = 247.5/1)

5 0
3 years ago
Read 2 more answers
A worker was paid a salary of $10,500 in 1985. Each year, a salary increase of 6% of the previous year's salary was awarded. How
Mazyrski [523]
Note that 6% converted to a decimal number is 6/100=0.06. Also note that 6% of a certain quantity x is 0.06x.

Here is how much the worker earned each year:


In the year 1985 the worker earned <span>$10,500. 

</span>In the year 1986 the worker earned $10,500 + 0.06($10,500). Factorizing $10,500, we can write this sum as:

                                            $10,500(1+0.06).



In the year 1987 the worker earned

$10,500(1+0.06) + 0.06[$10,500(1+0.06)].

Now we can factorize $10,500(1+0.06) and write the earnings as:

$10,500(1+0.06) [1+0.06]=$10,500(1.06)^2.


Similarly we can check that in the year 1987 the worker earned $10,500(1.06)^3, which makes the pattern clear. 


We can count that from the year 1985 to 1987 we had 2+1 salaries, so from 1985 to 2010 there are 2010-1985+1=26 salaries. This means that the total paid salaries are:

10,500+10,500(1.06)^1+10,500(1.06)^2+10,500(1.06)^3...10,500(1.06)^{26}.

Factorizing, we have

=10,500[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]=10,500\cdot[1+1.06+(1.06)^2+(1.06)^3+...+(1.06)^{26}]

We recognize the sum as the geometric sum with first term 1 and common ratio 1.06, applying the formula

\sum_{i=1}^{n} a_i= a(\frac{1-r^n}{1-r}) (where a is the first term and r is the common ratio) we have:

\sum_{i=1}^{26} a_i= 1(\frac{1-(1.06)^{26}}{1-1.06})= \frac{1-4.55}{-0.06}= 59.17.



Finally, multiplying 10,500 by 59.17 we have 621.285 ($).


The answer we found is very close to D. The difference can be explained by the accuracy of the values used in calculation, most important, in calculating (1.06)^{26}.


Answer: D



4 0
3 years ago
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