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DaniilM [7]
2 years ago
6

Choose the value of x for f(x)= x^2-3x when f(x) = 10.

Mathematics
1 answer:
Irina-Kira [14]2 years ago
5 0

Answer:

f(10)=70

Step-by-step explanation:

f(x)=x^{2} -3x\\f(10)=10^{2} -3(10)\\f(10)=100-30=70

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S_A_V [24]

The equation of the parallel line is y = –2x – 11.

Solution:

Given equation of the line is y = –2x – 5.

Slope of this line is (m_1) = –2

To write the equation parallel to this line and passes through (–4, –3).

<em>If two lines are parallel, then they have the same slope.</em>

\Rightarrow m_1=m_2

\Rightarrow m_2 =-2

<u>Point-slope formula:</u>

y-y_1=m(x-x_1)

Substitute the given values in the formula, we get

y-(-3)=-2(x-(-4))

y+3=-2(x+4)

y+3=-2x-8

Subtract 3 from both sides of the equation.

y+3-3=-2x-8-3

y=-2x-11

Hence the equation of the parallel line is y = –2x – 11.

5 0
3 years ago
The perimeter of a quadrant of a circle is 37.5 cm. Find the area of the circle. (in cm square)
Irina18 [472]

Answer:

the answer isA≈111.91cm²

4 0
2 years ago
X^2 = 25<br> ------<br> 289<br> (Solve for x)
Kisachek [45]
4114.5 Balance method used
4 0
3 years ago
A boat traveled 147 miles downstream and back. The trip downstream took 7 hours. The trip back took 147 hours. Find the speed of
KonstantinChe [14]

Answer:

The speed of boat in still water is 11 miles per hour

The speed of current is 10 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by boat in downstream = d_1 = 147 miles

The time taken by boat in downstream trip = t_1 = 7 hours

The distance cover by boat in upstream = d_2 = 147 miles

The time taken by boat in upstream trip = t_2 = 147 hours

Let The speed of boat in still water =  s_1 = x mph

And  The speed of the current =  s_2 = y mph

Now, According to question

Speed = \dfrac{\textrm Distance}{\textrm Time}

For downstream

s_1 +  s_2 = \dfrac{d_1}{t_1}

or, x + y =   \dfrac{147}{7}

I.e x + y = 21   mph              ..........1

For upstream

s_1 +  s_2 = \dfrac{d_2}{t_2}

or, x - y =   \dfrac{147}{147}

I.e x - y = 1   mph              ..........2

Now, Solving Eq 1 and 2

I.e (x + y) + (x - y) = 21 + 1

Or, (x + x) + (y - y) = 22

Or, 2 x = 22

∴  x = \frac{22}{2}

I.e x = 11  mph

So, speed of boat = x = 11 miles per hour

Again, put The value of x in Eq 2

So,  x - y = 1   mph    

I.e   11 - y = 1

∴, y = 11 - 1

I.e y = 10 mph

So, speed of current = y = 10 miles per hour

Hence The speed of boat in still water is 11 miles per hour , and The speed of current is 10 miles per hour . Answer

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2 years ago
I need to have the answer to solve this
lozanna [386]
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2 years ago
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