The length of the land = the length of the waterfront + the length of dry land
The length of the land = L
The length of the waterfront = 0.65L
The length of the dry land = 70 feet
L = 0.65L + 70
L - 0.65L = 70
0.35L = 70
L = 70 ÷ 0.35
L = 200 feet
1) add.
for example -1 + -2 = - (||-1| + |-2||), which is -(1+2) or -3
2) subtract
for example 4 + -7 = -(||-7| + |4||), which is - |7 - 4| or -3
3) change
for example 3 - (- 2) = 3 + 2
4) -10
the sum is -10.25, which is closest to -10
80 * 70 percent = cookies sold
80 * .7 = cookies sold
56 = cookies sold
22300 because the tenths place is below five
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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