Write the log equation as an exponential equation. You do not need to solve for x.

Mathematics

1 answer:

V125BC [204]3 years ago

7 0

Answer:

(x-6)^3x-5 =6

Step-by-step explanation:

logb a=c ------> b^c =a

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What is the vertex form of y=2x^2-8x+1

bezimeni [28]

Answer:

$2(x-2)^2-7$

Step-by-step explanation:

$y=2x^2-8x+1$

When comparing to standard form of a parabola: $ax^2+bx+c$

$a=2$
$b=-8$
$c=1$

Vertex form of a parabola is: $a(x-h)^2+k$ , which is what we are trying to convert this quadratic equation into.

To do so, we can start by finding "h" in the original vertex form of a parabola. This can be found by using: $\frac{-b}{2a}$ .

Substitute in -8 for b and 2 for a.

$\frac{-(-8)}{2(2)}$

Simplify this fraction.

$\frac{8}{4} \rightarrow2$

$\boxed{h=2}$

The "h" value is 2. Now we can find the "k" value by substituting in 2 for x into the given quadratic equation.

$y=2(2)^2-8(2)+1$

Simplify.

$y=-7$

$\boxed{k=-7}$

We have the values of h and k for the original vertex form, so now we can plug these into the original vertex form. We already know a from the beginning (it is 2).

$a(x-h)^2+k\\ \\ 2(x-2)^2-7$

6 0

3 years ago

1. Is the line that passes through the points A(0,1) and B(2,5) parallel to the line that passes through the points C(0,7) and D

kifflom [539]

You are correct that the slope of line AB is 2. To find the slope of the line CD, we can apply the slope formula again (like I assume you did with AB).

$m=\frac{15-7}{4-0}=\boxed{2}$