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irga5000 [103]
4 years ago
13

Determine the number of solutions for the equation: -6(24x+18)=43(5+5x).

Mathematics
2 answers:
dangina [55]4 years ago
5 0
-<span>6(24x + 18) = 43(5 + 5x)

-144x - 108 = 215 + 215x

-108 - 215 = 215x + 144x

-323 = 359x 

x = - 323/359       </span>⇒ Answer B. One solution in <span>ℝ</span>         
Agata [3.3K]4 years ago
3 0
The answer is B 

<span>-6(24x+18)=43(5+5x)
-144x - 108 = 215 +215x
-108 = 215 + 359x
-323 = 359x 
-323/359 = x

If you would like me to explain more details i will!</span>
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Find the surface area of the cylinder
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Answer:

Step-by-step explanation:

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3 0
3 years ago
seven different gifts are to be distributed among 10 children. How many distinct results are possible if no child is to receive
Alik [6]

Answer:

120 distinct results are possible if no child is to receive more than one gifts.

Step-by-step explanation:

When the order is not important, we use the combination formula:

C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

The order is said to be not important if for example, John receiving the Buffalo Bills jersey and then Laura receiving the Cleveland Browns jersey is the same as Laura receiving the Cleveland Browns jersey before John receives the Buffalo Bills jersey.

In this problem, we have that:

Combinations of 7 from a set of 10 elements. So

C_{n,x} = \frac{n!}{x!(n-x)!}

C_{10,7} = \frac{10!}{7!(3)!} = 120

120 distinct results are possible if no child is to receive more than one gifts.

6 0
3 years ago
An artist has completed of a painting in 2 weeks. At what rate is she working?
GenaCL600 [577]
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7 0
3 years ago
Which expression shows a way to find 2,813 x 7?
sergey [27]

Answer: C)14,000 + 5,600 + 70 + 21

Step-by-step explanation:

2813=2000+800+10+3

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800*7=5600

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i hope it help ο(=•ω<=)ρ⌒☆

8 0
3 years ago
How to factor this expression <br><br>x^3 - 4x^2 + 4x - 16
Natalija [7]
X²(x - 4) +4 (x - 4)

(x² + 4) (x - 4)

First find the common terms that can enter into both x³ and 4x² then write its down in this case it’s x² that can enter x³ leaving only x _since x³/x² = subtract of the indices. x² will also enter 4x² leaving only four hence you having x² (x - 4)
then do the same for the next pair of terms giving you 4 that can enter into both 4 and 16
Leaving you with +4 (x - 4)

Now you can put the common terms together like so (x² + 4) and choose get one of the other two which are the same= (x - 4)
= (x² + 4) (x - 4)
8 0
3 years ago
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