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balandron [24]
3 years ago
11

I need help this question is due in 20 minutes

Mathematics
1 answer:
pshichka [43]3 years ago
8 0

Answer:

20,067.68

All I did was 23,200 and minus $195.77 15 times! Your welcome.

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Whats the answer?<br><br> 12m +5 =17
Serga [27]

Answer:

m=1

Step-by-step explanation:

12m+5=17

       -5  -5

12m=12

m=1

3 0
3 years ago
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HELP PLSS
atroni [7]

The balloon reaches a height of 7 feet at 0.1 seconds and 2.13 seconds

<h3>How to determine the time the balloon is at the height?</h3>

The equation of the function is given as

h(t)= -16t^2 + 35t + 5

The above equation is a quadratic equation

When the balloon is at a height of 7 feet, we have

h(t) = 7

So, we have the following equations

h(t)= -16t^2 + 35t + 5

h(t) = 7

Next, we plot the equations on a graph (see attachment)

The equations intersect at

t = 0.059 and t = 2.129

Approximate

t = 0.1 and 2.13

Hence, the times are 0.1 seconds and 2.13 seconds

Read more about quadratic equation at

brainly.com/question/15709421

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8 0
1 year ago
What are the disadvantages of fire
matrenka [14]
Can you provide more information? Where would the fire be? What type of fire?(wildfire, controlled fire) What is the purpose of the fire?
4 0
4 years ago
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A particular isotope has a​ half-life of 74 days. If you start with 1 kilogram of this​ isotope, how much will remain after 150
shtirl [24]

\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}


\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}

6 0
3 years ago
A recent study reported that 40% of community college students in the U.S. Receive federal loans to pay for college tuition and
sweet [91]

Answer:

How are you asking questions but no pictures.

Step-by-step explanation:

3 0
3 years ago
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