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seropon [69]
3 years ago
6

Please help!!! Brainliest for whoever is right! What is the sum of the rational expressions below?

Mathematics
1 answer:
fenix001 [56]3 years ago
6 0

Answer:

<h2>\frac{5 {x}^{2} + 5x + 3 }{3 {x}^{2}  + 3x}</h2>

Step-by-step explanation:

\frac{2x + 3}{3x}  +  \frac{x}{ x + 1}

Write all the numerators above the least common denominator

\frac{(x + 1)(2x + 3) + 3 {x}^{2} }{3x(x + 1)}

Multiply the parentheses

\frac{2 {x}^{2} + 3x + 2x + 3 + 3 {x}^{2}  }{3x(x + 1)}

Distribute 3x through the parentheses

\frac{2 {x}^{2}  + 3x + 2x + 3 + 3 {x}^{2} }{3 {x}^{2}  + 3x}

Collect like terms=\frac{5 {x}^{2} + 5x + 3 }{3 {x}^{2} + 3 x}

Hope this helps...

Good luck on your assignment...

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The Venn diagram shows the results of two events resulting from rolling a number cube.
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Answer:   P(A\cap B)=\frac{1}{3}

P(A)=\frac{1}{3}

P(B)=1

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Step-by-step explanation:

From the given figure it can be seen that

Total number on cube= n(S)=6

Intersection of A and B = n(A ∩ B)= 2

Therefore,

P(A\cap B)=\frac{n(A\cap B)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Also, The number of elements in A = 2

Therefore,

P(A)=\frac{n(A)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Similarly, The number of elements in B= 6

Therefore,

P(B)=\frac{n(B)}{n(s)}=\frac{6}{6}=1

The formula to find the conditional probability is given by :-

P(A|B)=\frac{P(A\cap B)}{P(B)}\\\\\Rightarrow P(A|B)=\frac{\frac{1}{3}}{1}=\frac{1}{3}

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