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masha68 [24]
3 years ago
12

NEED HELP WHAT’S THE RELATIONSHIP OF X AND Y PLEASE HELP MEE

Mathematics
1 answer:
lora16 [44]3 years ago
3 0

Answer:

i have autism and adhd and add and dmdd so plz dont yell at me that i did not answer it!!!

Step-by-step explanation:

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The March 11, 2011, earthquake in Japan caused a tsunami that crashed into the (cant say on here because it looks like a bad wor
Lesechka [4]

A radioactive atmosphere around the area and an expensive, hard time cleaning everything up.

4 0
2 years ago
If you have a vase in the shape of a cube, and it hold 64 cubic centimeters of water. What is the side length of the vase?
goblinko [34]

Answer:

16

Step-by-step explanation:

take 64 and divide by two to get one of your sides. this leaves you with 32 and that is your area of one side. then divide 32 by 2 to get your side length of 16. hope this helps :)

8 0
3 years ago
Anybody know how to do this? I need help!
KengaRu [80]
Hope this would help you

7 0
3 years ago
Help please with # 24, 25, 26, 27
Elis [28]
24. C

25. B

26. A

27. C

I hope this helped!
6 0
3 years ago
Solve to find x <br> log (3x+5) to base 5= 2log (1-3x) to base 25
Eduardwww [97]

Answer:

x = -2/ 3

Step-by-step explanation:

in order to cancel out the logs they should have common bases

\mathsf{ log_{5}(3x + 5) = 2 log_{25}(1 - 3x)  }

we can write 25 as 5²

\mathsf{ \implies  log_{5}(3x + 5) =  2 \: log_{ {5}^{2} }(1 - 3x)  }

we know that the reciprocal of the exponents of the bases are multiplied to the log

\mathsf{ \implies  log_{5}(3x + 5) =   \frac{1}{\cancel{2} } \times \cancel{2} \: log_{ 5}(1 - 3x)  }

and now since the logs have common bases

\mathsf{ \implies  \cancel { log_{5}}(3x + 5) = \cancel{ log_{ 5}}(1 - 3x)  }

we're left with

\mathsf{ \implies 3x + 5 = 1 - 3x}

\mathsf{ \implies 9x = -4}

<u>x = -2/ 3</u>

8 0
3 years ago
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