Phythagoras theorem:
hypotenuse²=leg₁²+leg₂²
Data:
leg₂=7.2
hypotenuse=11.1
Therefore:
(11.1)₂=leg₁² +(7.2)²
123.21=leg₁²+51.84
leg₁²=123.21 - 51.84
leg₁²=71.37
leg¹=√(71.37)
leg₁=8.4
Answer: b=8.4
Answer:
0.8340
Step-by-step explanation:
The aim of this question is to find the probability that the student makes it to the second class prior to when the lecture commences.
Provided that A, B, and C are independent of each other from the full complete question.
Then; we want P(A + C < B)
So A 
N (2, 1.5)
B N (10, 1)
C N (6, 1)
P(A + C - B < 0)
Since they are normally distributed( i.e. A + C - B)
Then;
E(A + C -B) = E(A) + E(C) - (B)
E(A + C -B) = 2 - 10 + 6
E(A + C -B) = -2
Var(A+C -B) = Var(A) + Var (B) + Var (C)
Var(A + C -B) = (1.5)² + (1)² + (1)²
Var(A + C -B) = 4.25
The standard deviation = 
The standard deviation = 2.06155
Will first you should add then multiple and you should get your answer right just make sure you check it before you give it to the teacher
Answer:
42 Dimes, 10 Nickels.
Step-by-step explanation:
Dimes are worth $0.10, nickels are worth $0.05.
If D = number of dimes, and N = number of nickels, then the following equations are true:
0.10D + 0.05N = 4.70
D + N = 52
Next, let's multiply the first equation by 10 so that we can subtract the second one from it.
D + 0.50N = 47
(-) D + N = 52
Subtracting the second equation from the first one gives:
-0.5N = -5
-0.5N/-0.5 = -5/-0.5
N = 10
Finally, substitute N in the original second equation to find D.
D + 10 = 52
D + 10 - 10 = 52 - 10
D = 42
