Answer:
3x + 1 = 7
x = 2
Step-by-step explanation:
equation for the hanger diagram
3x + 1 = 7
Subtract 1 from both sides
3x = 6
Divide both sides by 3
x = 2
Answer:
a. 1965
b. 8 years
Step-by-step explanation:
For answers to questions like these it can work to consider the smallest possible dataset.
<h3>Dataset</h3>
For our purpose, consider the 9 years/values to be averaged to be ...
1, 2, 3, 4, 5, 6, 7, 8 ,9
<h3>Observations</h3>
a. The center value of the data set is 5. Its number is 5-1=4 more than the first one.
The first centered value is from the year 1961 +4 = 1965.
b. The 4 values at the beginning, and the 4 values at the end do not have a corresponding "average" value. That is, 4+4 = 8 values in the series are lost with respect to the number of average values.
8 years of values are lost.
Complementary angles equal 90 degrees.
The other angle would be 90 - 70.2 = 19.8 degrees
Answer: 895 phones
Step-by-step explanation:
Given that :
The function : y = 1.28e^1.31x ; is used to model the number of camera phones shipped since 1997
y = number of camera phones ; x = number of years since 1997
The number of camera phones shipped in the year 2002 can be obtained thus ;
x = 2002 - 1997 = 5 years
y = 1.28e^(1.31 * 5)
y = 1.28e^6.55
y = 1.28(699.24417)
y = 895.03254
y = 895 phones
Answer:
Amount left in bag one = 20kg
Amount left in bag 2 = 40 kg
Step-by-step explanation:
We are told that Two bags had 50 kilograms of sugar each.
Let first bag be x and second bag be y.
Now, we are told that After taking out 3 times as much sugar from bag one than bag two, bag one had half as much sugar left as bag two.
Thus, amount taken from bag one is;
3a and amount taken from bag two is a.
Amount left in bag 1 is;
50 - 3a while amount left in bag 2 is 50 - a.
Since bag one had half as much sugar left as bag two, then;
50 - 3a = ½(50 - a)
50 - 3a = 25 - 0.5a
50 - 25 = 3a - 0.5a
25 = 2.5a
a = 25/2.5
a = 10
Thus;
Amount left in bag 1 = 50 - 3a = 50 - 3(10) = 50 - 30 = 20 kg.
Amount left in bag 2 = 50 - a = 50 - 10 = 40 kg
