Answer:
1. 
2. 
3. 
Step-by-step explanation:
<h3> The complete exercise is: "Brown rice costs $2 per pound, and beans cost $1.60 per pound. Lin has $10 to spend on these items to make a large meal of beans and rice for a potluck dinner. Let b be the number of pounds of beans Lin buys and r be the number of pounds of rice she buys when she spends all her money on this meal.</h3><h3>1. Write an equation relating the two variables.</h3><h3>2. Rearrange the equation so "b" is the independent variable.</h3><h3>3. Rearrange the equation so "r" is the independent variable."</h3><h3 />
1. According to the information exercise given in the exercise, the cost per pounds of brown rice is $2. Since "r" represents the number of pounds of rice Lin buys, the total cost of the brown rice she buys can be represented with this expression:
The beans cost $1.60 per pound. Since "b" represents the number of pounds of beans Lin buys, the total cost of beans she buys can be represented as:
Knowing that she spends $10, you can write the following equation:
2. In order to rearrange the equation so "b" is the independent variable, you need to solve for "r":
3. To rearrange the equation so "r" is the independent variable, you must solve for "b". You get:
Comparing map distance to real distance we get 2cm/4km. That means 1cm = 2km.
So the map distance is half the real distance (well, technically not as one is in cm and the other in km but it’s enough to think this way) and a real distance of 10km must mean a map distance of half that (again ignoring the units) so we get 5cm.
Answer:
4 chocolates
Step-by-step explanation:
Before Luke started eating, there were 8. This is 2/3 of what Sara had to start with, so she started with 12. That is 3/4 of what Mike started with, so he started with 16.
Jill left 4/5 of what she started with, so she must have started with 20. Jake ate 1/6 and left 5/6, so 20 is 5 times the number Jake ate.
Jake ate 4 chocolates.
___
Jill ate 4; Mike ate 4; Sara ate 4; and Luke ate 4.
Answer: A. x= 5"
Step-by-step explanation:
ORIGINAL/NEW = 11"/7" = 8.5"/x
x = 7" x 8.5"/11" = 59.5"/11 = 5.409 ≅ 5.41"
If we wanted to keep most of the engraving, we would adjust the larger dimension, but we have been asked to adjust one dimension to 5", since it is said that C. x = 5.41 is incorrect
Then we will adjust the minor dimension to 5"
ORIGINAL/NEW = 11"/y = 8.5"/5"
y= 11" x 5"/8.5" = 6.47"
Then the new dimensions of the paper are 6.47" x 5" to fit an 7" x 5" frame
Answer: A. x= 5"
The mean, variance, and standard deviation are 1, 8,33 and 2.89
<h3>How to find the mean, variance, and standard deviation?</h3>
The distribution is given as:
[a, b] = [-4, 6]
The mean is calculated as;
Mean = (a + b)/2
So, we have
Mean = (-4 + 6)/2
Evaluate
Mean = 1
The variance is calculated as;
Var = (b - a)^2/12
So, we have
Var = (6 + 4)^2/12
Evaluate
Var = 8.33
The standard deviation is calculated as;
SD= sqrt(Var)
So, we have
SD = sqrt(8.33)
Evaluate
SD = 2.89
Hence, the mean, variance, and standard deviation are 1, 8,33 and 2.89
Read more about uniform distribution at:
brainly.com/question/16238191
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