Answer:
from my opinion second option is right
You have to set it up as two problems then combined like terms then add them together
Solution :
Demand for cola : 100 – 34x + 5y
Demand for cola : 50 + 3x – 16y
Therefore, total revenue :
x(100 – 34x + 5y) + y(50 + 3x – 16y)
R(x,y) = 

In order to maximize the revenue, set



.............(i)


.............(ii)
Solving (i) and (ii),
4 x (i) ⇒ 272x - 32y = 400
(ii) ⇒ (-<u>) 8x - 32y = -50 </u>
264x = 450
∴ 

So, x ≈ $ 1.70 and y = $ 1.99
R(1.70, 1.99) = $ 134.94
Thus, 1.70 dollars per cola
1.99 dollars per iced ted to maximize the revenue.
Maximum revenue = $ 134.94
Firstly, you know you have 27 (35/100)
Make this an improper fraction. 2735/100
Simplify this as much as you can. 547/20
Find how many times 20 will go into 540, and use the 7/20 as the fraction part of your mixed number.
Now, make as many whole as you can and states your remaining. 27 7/20