m = (y2-y1)/(x2-x1)
m = (6-4)/(4-0)
m = 2/4
y = mx + c
6 = (2/4)(4) + c
c = 4
Thus, the equation is y = (2/4)x +4
This is what i would do i would do this is every student has 40 then 1 student has 40 then he gets a movie ticket so 40 - 5 = 35 then he buys candy for 7.50 so 35 - 7.50 = 27.5 then buys a 2 dollar trolley ride so 27.5 - 2 = 25.5 so every student was left with 25 dollars and 5 cents
M^2 + 12m + 35
Factored:
(m+5)(m+7)
Check:
(m+5)(m+7)
(m*m) + (m*7) + (5*m) + (5*7)
m^2 + 12m + 35
Hope this helps! :)
See photo for solution and steps
Answer:
The height of water in the second tank is 2ft
Step-by-step explanation:
In this question, we are asked to calculate the height of water in a second tank if the content of a first tank is poured into the second tank.
The plot twist to answering this question is that we need to note the volume of water in the first tank. Although the first tank has dimensions of 2ft by 3ft by 2ft height, the water in the tank only rose to a height of 1 feet.
Hence, to calculate the volume of the water in the first tank, the width and the length of the tank still remain the same, the only difference here is that we work with a height of 1 feet since the Water is not full.
Mathematically, the volume of water present in the tank will be;
V = l * b * h
V = 4 * 3 * 1 = 12 cubic feet
Now, this content is emptied into a second tank. Since the volume of water here is the same; this means;
12 cubic feet = 3 * 2 * h
We ignore the 4ft height as it is just the height of the tank and not the height of the water in the tank
6h = 12 cubic feet
h = 12/6 = 2 ft
