(4y-3)(2y²+3y-5)
First , let's start with "4y"
4y*2y² = 8y³
4y*3y = 12y²
4y*-5 = -20y
Next, let's multiply by "-3"
-3*2y² = -6y²
-3*3y = -9y
-3*-5 = 15
Now, let's combine all of our values.
8y³+12y²-6y²-20y-9y+15 = 8y³+6y²-29y+15
Blue: = because the equal sign is stating that it’s the same.
It’s A because I did the test lmafo
#1 first we need to solve for slope which is y2-y1/x2-x1
plug in the coordinates and get 1-6/5-(-2) which makes our slope -5/7
then use the equation for point slope form which is:
y-y1=m(x-x1)
then plug in one of the coordinates, I'll use (-2,6), now we have
y-6=-5/7(x+2)
now to make this slope intercept, we just have to solve
y-6=-5/7x-10/7
y=-5/7x+4 4/7
repeat all these steps for 2 and 3
#2: slope = -13/5
plug it in to point slope and get: y+8=-13/5(x-3)
slope intercept:
y+8= -13/5x + 39/5
y= -13/5x -1/5
#3: slope = 3/4
point slope form: y-2=3/4(x-3)
slope intercept: y-2=3/4x-9/4 --> y=3/4x-1/4
Answer:
Step-by-step explanation:
We would assume that triangle ABC is a right angled triangle. This means that we can apply Pythagoras theorem in determining the unknown side length.
For the case of the minimum side length, we would assume that the unknown length, L is one of the shorter legs of the triangle. By applying Pythagoras theorem, it becomes
11² = 9² + L²
L² = 121 - 81 = 40
L = √40 = 6.32
For the case of the maximum side length, we would assume that the unknown length, L is one of the hypotenuse of the triangle. By applying Pythagoras theorem, it becomes
L² = 9² + 11²
L² = 81 + 121 = 202
L = √202 = 14.21
The minimum side length is 6.32 and the maximum side length is 14.21
