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Phantasy [73]
3 years ago
12

I need help on solving this math problem.​

Mathematics
1 answer:
son4ous [18]3 years ago
5 0

Answer:

f(1)=-3

f(-4)=-11

f(6)=0

Step-by-step explanation:

Use the correct formula depending on what (x) equals.

When (x=1) you use the second formula because 1 is greater than -2 but less than 4

When (x=-4) you use the first formula because -4 is less than -2

When (x=6) you use the third formula because 6 is greater than 4

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Can someone tell me how to do it, i have more problems like this​
BigorU [14]

Answer:

\large\boxed{\dfrac{7n}{30}=\dfrac{7}{30}n}

Step-by-step explanation:

\dfrac{2n}{5}+\left(-\dfrac{n}{6}\right)=\dfrac{2n}{5}-\dfrac{n}{6}

To subtract both fractions we need a common denominator.

LCD=(5)(6)=30

\dfrac{2n}{5}=\dfrac{2n\cdot6}{5\cdot6}=\dfrac{12n}{30}\\\\\dfrac{n}{6}=\dfrac{n\cdot5}{6\cdot5}=\dfrac{5n}{30}

Therfore

\dfrac{2n}{5}-\dfrac{n}{6}=\dfrac{12n}{30}-\dfrac{5n}{30}=\dfrac{12n-5n}{30}=\dfrac{7n}{30}=\dfrac{7}{30}n

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