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![\qquad\qquad\huge\underline{{\sf Answer}}](https://tex.z-dn.net/?f=%5Cqquad%5Cqquad%5Chuge%5Cunderline%7B%7B%5Csf%20Answer%7D%7D)
Let's solve ~
We need to find volume of the given Cylinder, with information :
![\qquad \sf \dashrightarrow \:Volume_{(Cylinder)} = \pi r²h](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3AVolume_%7B%28Cylinder%29%7D%20%3D%20%5Cpi%20r%C2%B2h)
![\qquad \sf \dashrightarrow \:Volume_{(Cylinder)} = \pi \sdot(12) {}^{2} \sdot17](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3AVolume_%7B%28Cylinder%29%7D%20%3D%20%20%5Cpi%20%5Csdot%2812%29%20%7B%7D%5E%7B2%7D%20%20%5Csdot17)
![\qquad \sf \dashrightarrow \:Volume_{(Cylinder)} = \pi \sdot144{}^{} \sdot17](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3AVolume_%7B%28Cylinder%29%7D%20%3D%20%20%5Cpi%20%5Csdot144%7B%7D%5E%7B%7D%20%20%5Csdot17)
![\qquad \sf \dashrightarrow \:Volume_{(Cylinder)} = 2448 \pi \: \: unit {}^{3}](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3AVolume_%7B%28Cylinder%29%7D%20%3D%202448%20%5Cpi%20%20%5C%3A%20%20%5C%3A%20unit%20%7B%7D%5E%7B3%7D%20)
So, correct choice is B
Answer:
Step-by-step explanation:
where is the work
Answer:
![a_n = 8 + (n - 1) (-6)](https://tex.z-dn.net/?f=a_n%20%3D%208%20%2B%20%28n%20-%201%29%20%28-6%29)
Step-by-step explanation:
Given
![a_1 = 8](https://tex.z-dn.net/?f=a_1%20%3D%208)
Recursive: ![a_{n} = a_{n-1} - 6](https://tex.z-dn.net/?f=a_%7Bn%7D%20%3D%20a_%7Bn-1%7D%20-%206)
Required
Determine the formula
Substitute 2 for n to determine ![a_2](https://tex.z-dn.net/?f=a_2)
![a_{2} = a_{2-1} - 6](https://tex.z-dn.net/?f=a_%7B2%7D%20%3D%20a_%7B2-1%7D%20-%206)
![a_{2} = a_{1} - 6](https://tex.z-dn.net/?f=a_%7B2%7D%20%3D%20a_%7B1%7D%20-%206)
Substitute ![a_1 = 8](https://tex.z-dn.net/?f=a_1%20%3D%208)
![a_2 = 8 - 6](https://tex.z-dn.net/?f=a_2%20%3D%208%20-%206)
![a_2 = 2](https://tex.z-dn.net/?f=a_2%20%3D%202)
Next is to determine the common difference, d;
![d = a_2 - a_1](https://tex.z-dn.net/?f=d%20%3D%20a_2%20-%20a_1)
![d = 2 - 8](https://tex.z-dn.net/?f=d%20%3D%202%20-%208)
![d = -6](https://tex.z-dn.net/?f=d%20%3D%20-6)
The nth term of an arithmetic sequence is calculated as
![a_n = a_1 + (n - 1)d](https://tex.z-dn.net/?f=a_n%20%3D%20a_1%20%2B%20%28n%20-%201%29d)
Substitute
and ![d = -6](https://tex.z-dn.net/?f=d%20%3D%20-6)
![a_n = a_1 + (n - 1)d](https://tex.z-dn.net/?f=a_n%20%3D%20a_1%20%2B%20%28n%20-%201%29d)
![a_n = 8 + (n - 1) (-6)](https://tex.z-dn.net/?f=a_n%20%3D%208%20%2B%20%28n%20-%201%29%20%28-6%29)
Hence, the nth term of the sequence can be calculated using![a_n = 8 + (n - 1) (-6)](https://tex.z-dn.net/?f=a_n%20%3D%208%20%2B%20%28n%20-%201%29%20%28-6%29)