The incorrect rounding for 53.864 is 53.87
<h3>How to approximation a decimal?</h3>
The decimal to be approximated is as follows;
53.864
The first option rounded the decimal to 2 significant figures or a whole number.
The second option is incorrect because they rounded it wrongly to 2 decimal places. The correct 2 decimal round is 53.86.
The third option is approximated rightly to one decimal place.
The last option is rounded to the closes tens term.
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Answer:
radius = 7.998170905 or about 8 units of measurement
Answer:
Therefore the probability that a pen from the first box and a crayon from the second box are selected is ![\frac5{16}](https://tex.z-dn.net/?f=%5Cfrac5%7B16%7D)
Step-by-step explanation:
Probability:
The ratio of the number of favorable outcomes to the number all possible outcomes of the event.
![Probability=\frac{\textrm{The number favorable outcomes}}{\textrm{The number all possible}}](https://tex.z-dn.net/?f=Probability%3D%5Cfrac%7B%5Ctextrm%7BThe%20number%20favorable%20outcomes%7D%7D%7B%5Ctextrm%7BThe%20number%20all%20possible%7D%7D)
Given that,
Three plain pencils and 5 pens are contained by the first box.
Total number of pens and pencils is =(3+5)=8
The probability that a pen is selected from the first box is
=P(A)
![=\frac{\textrm{The number pens}}{\textrm{Total number of pens and pencils}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Ctextrm%7BThe%20number%20pens%7D%7D%7B%5Ctextrm%7BTotal%20number%20of%20pens%20and%20pencils%7D%7D)
![=\frac{5}{8}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B5%7D%7B8%7D)
A second box contains three colored pencils and three crayons.
Total number of pencils and crayons is =(3+3)=6
The probability that a crayon is selected from the second box is
=P(B)
![=\frac{\textrm{The number of crayon}}{\textrm{Total number of crayons and pencils}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Ctextrm%7BThe%20number%20of%20crayon%7D%7D%7B%5Ctextrm%7BTotal%20number%20of%20crayons%20and%20pencils%7D%7D)
![=\frac{3}{6}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3%7D%7B6%7D)
Since both events are mutually independent.
The required probability is multiple of the events
Therefore the required probability is
![=\frac58\times \frac36](https://tex.z-dn.net/?f=%3D%5Cfrac58%5Ctimes%20%5Cfrac36)
![=\frac5{16}](https://tex.z-dn.net/?f=%3D%5Cfrac5%7B16%7D)
Answer:
6
Step-by-step explanation:
3/4 ÷ 1/8
Copy dot flip
3/4 * 8/1
Rewriting
3/1 * 8/4
3/1 * 2/1
6
Answer:
yes, ±2
Step-by-step explanation:
The x-intercepts are found by setting y=0 and solving for x:
x^2/4 = 1
x^2 = 4
x = ±√4
x = ±2
The x-values of interest are -2 and +2.