Person A could have any SIX dif. people sitting to her left. the person on A's left can have FIVE dif.people sit on his left. that person could have any of the remaining FOUR to her left and so on to the last person. so, there are 6x5x4x3x2x1= 720 possible arrangments.
Answer:
x³ - 10x² + 31x - 30
Step-by-step explanation:
Given
(x - 2)(x - 3)(x - 5) ← expand the second pair of factors using FOIL
= (x - 2)(x² - 8x + 15) ← distribute
= x³ - 8x² + 15x - 2x² + 16x - 30 ← collect like terms
= x³ - 10x² + 31x - 30
A.23/6
b.23/8
c.26/5
d.64/9
340+.06(sales)
340+.06(660)
$379.60
