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3 years ago

8.517 in two other ways

Mathematics

1 answer:

vichka [17]3 years ago

5 0

8.517 as a Fraction:8 and 500/1000 ( This is a mixed number)
8.517 as a Percentage: 815.7%

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Frederick designed an experiment in which he spun a spinner 20 times and recorded the results of each spin.

belka [17]

Answer:

the statements given above are true.

Step-by-step explanation:

Given that Frederick designed an experiment in which he spun a spinner 20 times and recorded the results of each spin.

He spun a 4 five times.

The statements true are:

i) For the experimental outcomes to be closer to the predicted outcome, the number of trials should be increased.

iii) If the number of trials is changed, the experimental probability also changes.

iv) If the number of trials is changed, the predicted number of outcomes also changes.

v) If the number of trials is changed, the number of experimental outcomes also changes.

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2 years ago

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The distance from the tip of a slice of pizza to the crust is 7 inches.

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1 year ago

What is the result of subtracting the second equation from the first?

Ronch [10]

Answer:

-5x + 0y = -11

The y terms are eliminated

Step-by-step explanation:

- 4x – 2y = -2

X - 2y = 9

We want to subtract the second equation from the first

Distribute a minus sign to all the terms in the second equation

- 4x – 2y = -2

X - 2y = 9

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2 years ago

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

3 0

2 years ago