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Luda [366]
3 years ago
5

Find the values for a and b.

Mathematics
2 answers:
valentinak56 [21]3 years ago
8 0

Answer:

a = 68, b = 136

Step-by-step explanation:

The angle in the circle = 360°, thus

b = 360 - 224 = 136

The inscribed angle a between a tangent- chord is equal to half the measure of its intercepted arc, so

a = 0.5 × 136 = 68

IrinaK [193]3 years ago
6 0

Answer:

the value of a and b is 68

Step-by-step explanation:

the other half is 224 so you minus 360 from 224 which will give us 136 then you divide by 2 to get a and b.

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In the figure, three line segments cross at a common point. Angle A is 45°, and angle E is 85°. What is the measurement of angle
katen-ka-za [31]

Answer: Measure angle H = 42°


Step-by-step explanation:

"In a triangle, the measure of the exterior angle is equal to the sum of the measures of the two non-adjacent angles to the exterior angle"

In given we have,

angle E is an exterior angle to triangle DFH

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Based on the above rule,

measure angle E = measure angle D + measure angle H

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angle E = 87°

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Substitute with the givens in the above rule and solve for the measure of angle H as follows:

angle E = angle D + angle H

87° = 45° + measure angle H

measure angle H = 87° - 45°

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5 0
3 years ago
Find all values of x for which the series converges. (enter your answer using interval notation. ) [infinity] (4x)n n = 1
andreyandreev [35.5K]

The series converges to  1/(1-9x) for -1/9<x<1/9                  

Given the series is  ∑ 9x^{n} x^{n}

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We know,                

∑ ar^{n-1}    converges to  (a) / (1-r) if r < 1

Otherwise the series will diverge.

Here, ∑ (9x)^{n} is a geometric series with |r| = | 9x |

And it converges for |9x| < 1

Hence, the given series gets converge for -1/9<x<1/9

And geometric series converges to a/(1-r)

Here, a = 1 and r = 9x

Therefore, a/(1-r) = 1/(1-9x)

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For more information about convergence of series, visit

brainly.com/question/15415793

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2 years ago
Answer to -5x-6x&lt;8-8n-n
EastWind [94]
First...
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8 - 9n

-11x\ \textless \ 8-9n

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Simplify \ \textgreater \  x\ \textgreater \ \frac{-8+9n}{11}

Hope this helps!
6 0
4 years ago
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