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3 years ago

A 45-inch pipe is cut into two pieces. one piece is two times the length of the other. find the lengths of the two pieces.

Mathematics

2 answers:

natka813 [3]3 years ago

7 0

I think the answer is 22.5 if i get it wrong please resound back to me

luda_lava [24]3 years ago

3 0

One piece is 30in and the other is 15in, 30 is double 15

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3 years ago

7 3/9 - 2 4/9 = 11 3/4 - 5 1/4 =

jeka57 [31]

1.)

$7 \frac{3}{9} - 2 \frac{4}{9} \\ = \frac{66}{9} - \frac{22}{9} \\ = \frac{44}{9} \\ = 4 \frac{8}{9}$

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3 years ago

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Ira Lisetskai [31]

Answer:

$y(x)=C_1e^{-x}+C_2e^{3x}$

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To solve a second-order homogeneous differential equation, we need to substitute each term with the auxiliary equation $am^2+bm+c=0$ where the values of $m$ are the roots:

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3 years ago

A 45​-inch pipe is cut into two pieces. one piece is two times the length of the other. find the lengths of the two pieces.

A 45-inch pipe is cut into two pieces. one piece is two times the length of the other. find the lengths of the two pieces.