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Dovator [93]
4 years ago
15

2(x − 7) + (8x + 20)

Mathematics
1 answer:
Angelina_Jolie [31]4 years ago
5 0

Answer:

your answer should be 10x+6

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Determine the missing exponent<br>2^5=1/4​
Alinara [238K]

Answer:

false

Step-by-step explanation:

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If x = 1 is a zero of the polynomial function f(x) = 3x3 − 8x2 + 3x + 2, which of the following is another zero of f(x)? 
zubka84 [21]
Divide 3x^3 -8x^2+3x  + 2 by (x - 1)

THis gives the quotient   3x^2 - 5x - 2

3x^2 - 5x -  2  = (3x + 1)(x  - 2 )


so x = 2 is another root  


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How to master Algebra 1
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What is the projection of (2,6) onto (-1,5)?
kvv77 [185]

Answer: Projection of (2,6) onto (-1,5) is given by

\dfrac{28}{\sqrt{26}}

Step-by-step explanation:

Let \vec{a}=2\hat{i}+6\hat{j}

and \vec{b}=-1\jhat{i}+5\hat{j}

we need to find the projection of \vec{a} onto \vec{b}

As we know the formula for projection:

Projection=\frac{\vec{b}}{\mid b\mid}. \vec{a}

Since we know the value of  \vec{b}=-1\jhat{i}+5\hat{j}

so,

\mid b\mid=\sqrt{(-1)^2+(5)^2}\\\\\mid b\mid=\sqrt{1+25}\\\\\mid b \mid=\sqrt{26}

so, \dfrac{\vec{b}}{\mid b\mid}=\dfrac{-1\hat{i}+5\hat{j}}{\sqrt{26}}

Now, it becomes,

Projection=\dfrac{(2\ht{i}+6\hat{j}).(-1\hat{i}+5\hat{j})}{\sqrt{26}}\\\\Projection=\dfrac{-2+30}{\sqrt{26}}\\\\Projection=\dfrac{28}{\sqrt{26}}

Hence, projection of (2,6) onto (-1,5) is given by

\dfrac{28}{\sqrt{26}}

8 0
3 years ago
Round each number to the underline place value 3.789 seven being underline
kvasek [131]

Answer:

4

Step-by-step explanation:

the 7 is over 5 which makes the 3 round to a 4

3 0
3 years ago
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