Ask question

Ask question

All categories

2 years ago

5

mike opened a savings account and deposited $300.00. The account earns 11% interest, compounded annually. If he wants to use the

money to buy a new bicycle in 2 years, how much will he be able to spend on the bike?

1 answer:

Sever21 [200]2 years ago

5 0

He will be able to spend 366 for the bike because every year he gets 33 dollars(the 11% interest)

You might be interested in

Identify the quadratic function from the four functions

Alchen [17]

Quadratic Function is a function that takes the equation form of:

$\large \boxed{y = a {x}^{2} + bx + c}$

where a ≠ 0. However the form of Quadratic Function above can also be called "standard form" or general form because it is commonly used when defining the function. Quadratic Functions also have other two forms which are intercept form and vertex form.

<u>Vertex</u><u> </u><u>Form</u>

$\large \boxed{y = a {(x - h)}^{2} + k}$

<u>Intercept</u><u> </u><u>Form</u>

$\large \boxed{y = (ax - b)(bx - c)}$

The intercept form can be expressed as y = (x-a)(x-b) depending on the other perspective.

If you look at all four functions, you will notice that only two of functions have the second degree as highest degree while the third function has third degree as highest and fourth function has fourth degree. Recall the definition of Quadratic Function above that the highest degree of Quadratic Function can only be second degree (squared, x² as example). Therefore we can rule out the x³ and -2x⁴ away.

So our only quadratic functions are:

$\large{ \begin{cases}y = - {x}^{2} - 4 \\ y = {(x - 1)}^{2} - 7 \end{cases}}$

As for the f(x) = -x²-4. The equation is in standard form which is y = ax²+bx+c. The second equation is in vertex form which is y = a(x-h)²+k.

Answer

The only quadratic functions are f(x) = -x²-4 and f(x) = (x-1)²-7
-x²-4 is in standard form.
(x-1)²-7 is in vertex form.

Hope this helps and let me know if you have any doubts.

<em>Als</em><em>o</em><em> </em><em>let</em><em> </em><em>me</em><em> </em><em>know</em><em> </em><em>if</em><em> </em><em>you</em><em> </em><em>want</em><em> </em><em>me </em><em>t</em><em>o</em><em> </em><em>convert</em><em> </em><em>the</em><em> </em><em>function</em><em> </em><em>into</em><em> </em><em>other</em><em> </em><em>form</em><em>.</em><em> </em><em>For</em><em> </em><em>ex</em><em>.</em><em> </em><em>convert</em><em> </em><em>the</em><em> </em><em>vertex</em><em> </em><em>form</em><em> </em><em>to</em><em> </em><em>standard</em><em> </em><em>form</em><em>.</em><em> </em>

Happy Learning and Good Luck with your assignment!

4 0

2 years ago

Megan has practiced the piano for 7.5 hours over the course of this week. She practices on Tuesdays, Thursdays, and Saturdays. H

gulaghasi [49]

Answer:

150

Step-by-step explanation:

you have three days and 7.5 so decide 7.5 by 3 it equals 2.5 which in minutes is 150

7 0

2 years ago

Suppose that there are 15 antennas in a store, of which 3 are defective. Assume all the defectives and all the functional antenn

ohaa [14]

Answer:

Step-by-step explanation:

Total number of antenna is 15

Defective antenna is 3

The functional antenna is 15-3=12.

Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.

So,

We line up the 13 good ones, and see where the bad one will fits in

__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __

Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.

Then,

There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement

ⁿCr= n!/(n-r)!r!

The number of arrangement is

14C3=14!/(14-3)!3!

14C3=14×13×12×11!/11!×3×2

14C3=14×13×12/6

14C3=364ways

7 0

3 years ago

What is the <br> Midpoint of -3,8 -7,-6

Leni [432]

Answer:

(-5,1)

Step-by-step explanation:

5 0

2 years ago

HELP MEEE PLS recipe cslls for 2 cups of suger and makes 48 cookies recipe B calls for 3 cups of suger and makes 54 of the same

JulijaS [17]

Answer:

So, when we solve for x we see that we can make 16 cookies using 1 cup of sugar. Then, yes, as you suggested we could divide 30 cookies by this ratio to see that we need less than 2 cups of sugar to make 30 cookies: And, as you said, this value is less than 2 cups, the value under Quantity B. Good job! I hope this helps :)

Step-by-step explanation:

5 0

2 years ago