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❖ 24. D. 18 minutes 25. C. 12
To solve for number 24, you know that the teacher can grade 5 exams in 3 minutes. He's grading a total of 30 exams. We multiply 5 x 6 to get 30 and we also multiply 3 x 6 to get 18.
To solve for number 25, you know the Dukes have won 3 out of 5 of their last games. The season has 20 games so we multiply 5 x 4 to get 20 and 3 x 4 to get 12.
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748 inches... You do know there's a meter to inches converter online, right?
Answer:
Step-by-step explanation:
Discussion
What you have presented is called a cyclic quadrilateral. A cyclic quadrilateral is a 4 sided figure whose angles (4 of them) all touch the circumference of a circle.
Here's what you want to know. Two angles that are opposite each other are supplementary (they add to 180 degrees)
Equation
x + 80 = 180 Subtract 80 from both sides.
Solution
x + 80 - 80 = 180 - 80 Combine
x = 100
Answer
x = 100
Answer:
EB ≈ 1.563 in
Step-by-step explanation:
The diagonals of a rhombus divide the figure into four congruent right triangles. Angle DAB is bisected by EA, so angle EAB is 46°/2 = 23°. EB is the side opposite, so the relevant trig relation is ...
Sin = Opposite/Hypotenuse
sin(EAB) = EB/AB
EB = (4 in)sin(23°) . . . . . . multiply by the hypotenuse
EB ≈ 1.563 in
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get
= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],
applying L'Hospital rule again ,we get,
= > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2
For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.
Hence 2a - b =0 => 2a = b ------(A)
limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,
= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2
[0/0 form], applying L'Hospital rule again ,we get,
limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2
from (A), we have , 2a = b => 2a = -2 => a = -1
Hence a =-1 & b = -2