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lesya [120]
3 years ago
14

Which expression is equivalent to: 1/3

Mathematics
1 answer:
shepuryov [24]3 years ago
4 0

Answer:

(6x-3)-(4x+5)

6x-3-4x-5

6x-4x-3-5

2x-8

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Doing Ratios, rates, and unit rates please help me I need this done by tommorow but people don't wanna answer I've asked multipl
stiv31 [10]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

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❖ 24. D. 18 minutes  25. C. 12  

To solve for number 24, you know that the teacher can grade 5 exams in 3 minutes. He's grading a total of 30 exams. We multiply 5 x 6 to get 30 and we also multiply 3 x 6 to get 18.

To solve for number 25, you know the Dukes have won 3 out of 5 of their last games. The season has 20 games so we multiply 5 x 4 to get 20 and 3 x 4 to get 12.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

6 0
3 years ago
What is the answer please, thanks
Alex787 [66]
748 inches... You do know there's a meter to inches converter online, right?
3 0
3 years ago
How can I find the x value?<br>How can I explain it?<br><br>PLEASE ANSWER THE QUESTION!!!
Jlenok [28]
Answer:

Step-by-step explanation:
Discussion
What you have presented is called a cyclic quadrilateral. A cyclic quadrilateral is a 4 sided figure whose angles (4 of them) all touch the circumference of a circle.

Here's what you want to know. Two angles that are opposite each other are supplementary (they add to 180 degrees)

Equation
x + 80 = 180 Subtract 80 from both sides.

Solution
x + 80 - 80 = 180 - 80 Combine
x = 100

Answer
x = 100

8 0
2 years ago
In rhombus ABCD, diagonals AC and BD meet at point E. If the measure of angle DAB is 46 degrees, find the length of EB.
slamgirl [31]

Answer:

  EB ≈ 1.563 in

Step-by-step explanation:

The diagonals of a rhombus divide the figure into four congruent right triangles. Angle DAB is bisected by EA, so angle EAB is 46°/2 = 23°. EB is the side opposite, so the relevant trig relation is ...

  Sin = Opposite/Hypotenuse

  sin(EAB) = EB/AB

  EB = (4 in)sin(23°) . . . . . . multiply by the hypotenuse

  EB ≈ 1.563 in

3 0
2 years ago
Tough one!
frosja888 [35]
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get

= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],

applying L'Hospital rule again ,we get,

 = > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2

For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.

Hence 2a - b =0 => 2a = b ------(A)

limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,

= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2

[0/0 form], applying L'Hospital rule again ,we get,

limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2

from (A), we have , 2a = b => 2a = -2 => a = -1

Hence a =-1 & b = -2
7 0
3 years ago
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