We have to consider the equation of a line ( in slope - intercept form ) that is parallel to y = 3, and passes through the point ( 0, 6 ). Now y = 3 can be plotted as a horizontal line that passes through the point ( 0, 3 ). If we want a line that is parallel to this, it must be horizontal as well;

Let us consider the second point now. This line must pass through the point ( 0, 6 ). We can conclude that the line must be 1. Horizontal, and 2. Pass through point ( 0, 6 );

Equation - y = 6

7 0

3 years ago

Four points A, B, C, and D are coplanar, but only two at a time are collinear. Suppose a line is drawn through each pair of poin

Brut [27]

Based on the given details above, the number of lines that can be drawn through each pair of points would be six: Four sides and two diagonals. When we say coplanar points, these are points that lie in the same plane. This is made up of three or more points. Hope this answer helps.

4 0

3 years ago