x=3/4, y=1/3. (x,y)=(3/4,1/3)

Let's put these as improper fractions.
30 = 60/2. add the 1/2 to get 61/2
13 = 52/4. add the 3/4 to get 55/4

To add/subtract fractions, they must have the same denominator. (bottom no.)
If we multiply the top and bottom of a fraction by something, it stays equal.
We can conclude that 61/2 = 122/4. (bottom multilpies by 2, so does the top)

Now that we have a common denominator, we can subtract.
The "fourths" just sort of acts like a unit. Subtract 55 from 122 to get

.
We can convert this to an improper fraction simply by dividing 67 by 4.
This leaves us with 16, and a remainder of 3. Our answer is
Answer:
Step-by-step explanation:
Answer to Consider the area between the graphs x+6y=12 and x+4=y^2. ... This Can Be Computed As A Single Interval Where Alpha= Beta= And H(y)=
Answer:
a_1 = 0
a_2 = -1
a_3 = -6
a_4 = -31
a_5 = -156
Step-by-step explanation:
a_n=(5a_n-1)-1
a_1 = 0
to find a2 substitute a1
a_2 = (5* a_1)-1
a_2 = 5* 0 -1
a_2 = 0-1
a_2 = -1
to find a3 substitute a2
a_3 = (5* a_2)-1
a_3 = (5* -1 ) -1
a_3 = -5 -1
a_3 = -6
to find a4 substitute a3
a_4 = (5* a_3)-1
a_4 = (5* -6 ) -1
a_4 = -30 -1
a_4 = -31
to find a5 substitute a4
a_5 = (5* a_4)-1
a_5 = (5* -31 ) -1
a_5 = -155 -1
a_5 = -156