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Sloan [31]
4 years ago
10

ACTIVITY 1: What a Difference!

Mathematics
1 answer:
arsen [322]4 years ago
4 0

Answer:

1. -2

2.-10

3. 16

4. -29

5. 3

6. 11

7. 3

8. -4

9. 14

10. 25

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Expreess 3.81 as a mixed number
Luba_88 [7]

Answer:

3.81 = 3 81/100

Step-by-step explanation:

This can’t be simplified so it stays as 3 \frac{81}{100}

8 0
3 years ago
How do you do this? Thanks for your time and effort!
V125BC [204]
Well first you have to simplify the denominators with x, by multiplying the denominator on the left times the top and bottom of the middle, and vice versa to get 10x/(4x^2-4x)-9(2x-2)/(4x^2-4x)=-1/4 and then you combine the fractions on the left to get 2(9-4x)/(4x^2-4x)=-1/4 and then you cross multiply the fractions to get 8(9-4x)=-4x^2+4x and then simplify to get 72-32x=-4x^2+4x and then 4x^2-36x+72=0 which then we can turn into 4(x-6)(x-3)=0 so x is 6 and 3
3 0
4 years ago
Solve the system of equations by elimination. Show your work. i’ll give brainliest
My name is Ann [436]

Answer:

x = 5

y = 4

Step-by-step explanation:

multiply the second equation by -1 and add the first equation to eliminate "x"

4x+6y=44\\-4x-2y=-28
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       4y=16

y=16/4 =4

Replace "y" in the first equation:

4x+6(4)=44

4x+24=44

4x=44-24

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5 0
2 years ago
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At a bake sale, as student spent $11.00 buying 3 brownies and 5 cookies. His friend spent $3.95 buying 1 brownie and 2 cookies.
dybincka [34]

Answer:

$2.25

Step-by-step explanation:

Let "b" be the price of 1 brownie and "c" the price of 1 cookie.

At a bake sale, a student spent $11.00 buying 3 brownies and 5 cookies. Symbolicaly,

3 b + 5 c = 11.00   [1]

His friend spent $3.95 buying 1 brownie and 2 cookies. Symbolicaly,

1 b + 2 c = 3.95

b = 3.95 - 2c   [2]

If we replace [2] in [1], we get

3 (3.95 - 2c) + 5 c = 11.00

11.85 - 6c + 5c = 11.00

c = 0.85

If we replace c = 0.85 in [2], we get

b = 3.95 - 2 (0.85) = 2.25

8 0
3 years ago
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