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3 years ago

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Jo's house is located at (-4,-2), Elenas house is a reflection of Jo's house across the x-axis. What is the coordinate of Elenas

house?

1 answer:

Snowcat [4.5K]3 years ago

3 0

Answer:

The coordinates of Elena's house is (4,-2)

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What is the area of this polygon?

brilliants [131]

The area of this polygon is 35.5 units∧2.

Good luck!!!!

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3 years ago

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What is the answer <br> y-11=25-3y

Katen [24]

Answer:

9

Step-by-step explanation:

y-11=25-3y

y + 3y = 25 + 11

4y = 36

y = 36 / 4

y = 9

Hope it will help :)

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3 years ago

A geologist has ten rock samples in a bag and is going to use eight for class. What is the probability that the first three pull

Neporo4naja [7]

Answer:

1/56 chance

Step-by-step explanation:

3/8 x 2/7 x 1/6 = 1/56

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3 years ago

A bag contains six red marbles three blue marbles and five green marble the three marbles are drawn out of the bag what is the p

tia_tia [17]

Answer:

Step-by-step explanation:

Red = 6

Blue = 3

Green = 5

Total = 14

First marble = 6/14 = 3/7 You now have 5 reds and 13 total

Second Marble = 5 * 13 which brings you down to 4 red and 12 total.

Third Marble = 4/12 = 1/3

Result

P(3 Red) = 3/7 * 5/13 * 1/3 cancel the 3s

P(3 Red) = 1/7 * 5/13

P(3 Red) = 5/91

P(3 Red) = 0.0549 . Rounding to the nearest 1/100 depends on what you have been told about rounding. I would say the answer is 0.05 but your teacher may say something different.

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3 years ago

The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10

Rama09 [41]

Answer:

a) $E(X) = 6.45$

b) $E(X^{2} )= 57.25$

c) $V(X) = 15.648$

d) E(3X + 2) = 21.35

e) $E(3X^{2} +2) = 173.75$

f) V(3X+2) = 140.832

g) E(X+1) = 7.45

h) V(X+1) = 15.648

Step-by-step explanation:

a) $E(X) = \sum xP(x)$

$E(X) = (1*0.05) + (2*0.10) + (4*0.35) + (8*0.40) + (16*0.10)\\E(X) = 6.45$

b)

$E(X^{2} ) = (1^{2} *0.05) + (2^{2} *0.10) + (4^{2} *0.35) + (8^{2} *0.40) + (16^{2} *0.10)\\ E(X^{2} )= 57.25$

c)

$V(X) = E(X^{2} ) - (E(X))^{2} \\V(X) = 57.25 - 6.45^{2} \\V(X) = 15.648$

d)

$E(3X+2) = 3E(X) + 2\\E(3X+2) = (3*6.45) + 2 \\E(3X+2) = 21.35$

e)

$E(3X^{2} +2) = 3E(X^{2} ) + 2\\E(3X^{2} +2) = (3*57.25) + 2 \\E(3X^{2} +2) = 173.75$

f)

$V(3X+2) = 3^{2} V(X)\\V(3X+2) = 9*15.648\\V(3X+2) = 140.832$

g)

$E(X+1) = E(X) + 1\\E(X+1) = 6.45 + 1\\E(X+1) =7.45$

h)

$V(X+1) = 1^{2} V(X)\\V(X+1) = 15.648$

6 0

3 years ago