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Murljashka [212]
4 years ago
6

Jenny has nine marbles, but her best friend Susie gives her ten more! However, the neighborhood bully, Danny, steals four marble

s from her. Jenny's marbles are all of very high quality, so she trades each of her marbles for three of John's marbles apiece. The very next day is Jenny's birthday so she receives seven marbles from her parents, and finally gives two to her sister. How many marbles does she have now?
Mathematics
1 answer:
Dimas [21]4 years ago
8 0

Answer:

Jenny has 50 marbles

Step-by-step explanation:

I find it easiest to right down the numbers as I read the question,

(9+10-4) x3 +7-2

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Beth walked around her neighborhood. In 1/2 hour, she walked 1 1/4 miles. What was Beth’s rate in miles per hour
Vadim26 [7]

Answer:

2.5 miles per hour

Step-by-step explanation:

ok, so we already know how long she walked in 1/2 hour and we need to find out how many miles in one full hour. So, i multiplied 1 1/4 times two to make up the one full hour and I got 2.5 miles. So the rate is 2.5 mph.

4 0
3 years ago
Difference is 9, product is 22
expeople1 [14]
The answer is 2,444444444444444 
3 0
4 years ago
Read 2 more answers
Solve for x in the equation x2 - 12x+36 = 90.
cupoosta [38]

Answer:

<u>The correct answer is A. x = 6 + 3 √10</u>

Step-by-step explanation:

Let's solve for x:

x² - 12x + 36 = 90

Factoring this quadratic equation, we have:

(x - 6) (x - 6) = 90

(x - 6)² = 90

x - 6 = √90 (Square root to both sides of the equation)

x = 6 + √90 (Adding 6 to both sides of the equation)

x = 6 + √9 * 10

x = 6 + √3² * 10

x = 6 + 3 √10

<u>The correct answer is A. x = 6 + 3 √10</u>

5 0
4 years ago
Let n be the middle number of three consecutive integers. write an expression for the sum of these integers.
mash [69]
(n-1)+n+(n+1)
With n as the middle of 3 integers, n-1 is the integer just before n and n+1 is the integer just after n.
8 0
3 years ago
Read 2 more answers
Which of the following can be a Pythagorean triplets?:
PolarNik [594]

<h2>Answer :-</h2>

As we know that,

Pythagoras triplet

1) a² + b² = c²

Let

\sf \: {2}^{2} + {2}^{2} = {4}^{2}

\sf \: 4 + 4 = 16

  • 8 ≠ 16
<h3>Hence, A can't be Pythagoras triplet</h3>

2) a² + b² = c²

\sf \:5 {}^{2} + {12}^{2} = {13}^{2}

\sf \: 25 + 144 = 169

  • 169 = 169
<h3>Therefore, B can be Pythagoras triplet</h3>

3)a² + b² = c²

\sf {3}^{2} + {5}^{2} = {6}^{2}

\sf 9 + 25 = 36

  • 34 ≠ 36
<h3>Hence, C can't be Pythagoras triplet</h3>

4) a² + b² = c²

\sf {5}^{2} + {4}^{2} = {7}^{2}

\sf \: 25 + 16 = 49

  • 41 ≠ 49
<h3>Hence, D can't be Pythagoras triplet</h3>

<h2 /><h2>Therefore :-</h2>

Only B can be Pythagoras triplet.

3 0
3 years ago
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