Answer:
<em>Sorry, If this late but here's the answer. The data plots represent the hours students study each week in two different classrooms. The mean number of hours a student in Mr. Hart’s class studies is </em><em>4.6</em><em> hours. The mean number of hours a student in Ms. Perry’s class studies is </em><em>2.8</em><em> hours. A typical student in Mr. Hart’s class studies </em><em>More than</em><em> a typical student in Ms. Perry’s class. </em><em>Good Luck!</em>
<em>Here's the photo... </em>
ANSWER: 219.375
subtract the second day from the first day.
547.250-327.875=219.375
Given:
Diameter of the hole = 30 cm
To find:
The area of the hole.
Solution:
The radius of a circle is always half of the diameter. It is given that the diameter of the hole is 30 cm. So, the radius of the hole is:
Area of a circle is:
Putting 
and in the above formula, we get
Therefore, the area of the hold is 706.5 square cm.
The proportion would be 1/3 and x/9. Cross multiplication creates 3x=9. Divide both sided by three, and there are 3 trombones in the orchestra.
Answer: -2
Step-by-step explanation:
The information in the question can be used to form an equation which goes thus:
2nd term = a + d = 4 ...... i
5th term = a + 4d = 22 ....... ii
From equation i
a = 4 - d ........ iii
Put equation iii into ii
a + 4d = 22
(4 - d) + 4d = 22
4 - d + 4d = 22
4 + 3d = 22
3d = 22 - 4
3d = 18
d = 18/3
d = 6
Commons difference is 6
Since a + d = 4
a + 6 = 4
a = 4 - 6
a = -2
The first term is -2
