Find the distance between the points: (-3, -4) and (5, 5)
1 answer:
Answer:d = √ ((X2-X1)2+(Y2-Y1)2)
d = √ (5--3)2+(5--4)2
d = √ ((8)2+(9)2)
d = √ (64+81)
d = √ 145
Xm=(X1+X2)/2
Xm=(-3+5)/2=1
Ym=(Y1+Y2)/2
Ym=(-4+5)/2=0.5
Slope = (Y2-Y1) = (5--4) = (9) = 1.125
(X2-X1) (5--3) (8)
The midpoint is: (1,0.5)
y = mx + b
y = 1.13x + b
-4 = 1.13×-3 + b
-4 = -3.38 + b
-4--3.38 = b
-0.63 = b
y= 1.13x-0.63
y= 1.13x-0.63
0= 1.13x-0.63
-1.13x= -0.63
x= -0.63/-1.13 = 0.56
y= 1.13×0-0.63
y= -0.63
Step-by-step explanation:
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3. 5
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6. -3
Answer:
They have the same x value.
Step-by-step explanation:
First, you have to find the LCD. The LCD of 4 and 7 is 28, so you rewrite the fraction:
7/28
4/28
Then you add them.
Answer:
(6+11c)^2
hope this helps :)
