Question

Find the distance between the points: (-3, -4) and (5, 5)

Answer 1

Answer:d = √  ((X2-X1)2+(Y2-Y1)2)

d = √ (5--3)2+(5--4)2

d = √ ((8)2+(9)2)

d = √ (64+81)

d = √ 145

Xm=(X1+X2)/2

Xm=(-3+5)/2=1

Ym=(Y1+Y2)/2

Ym=(-4+5)/2=0.5

Slope =  (Y2-Y1)  =  (5--4)  =  (9)  = 1.125

(X2-X1) (5--3) (8)

The midpoint is: (1,0.5)

y = mx + b

y = 1.13x + b

-4 = 1.13×-3 + b

-4 = -3.38 + b

-4--3.38 = b

-0.63 = b

y= 1.13x-0.63

y= 1.13x-0.63

0= 1.13x-0.63

-1.13x= -0.63

x= -0.63/-1.13 = 0.56

y= 1.13×0-0.63

y= -0.63

Step-by-step explanation: