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2 years ago

Find the distance between the points: (-3, -4) and (5, 5)

Mathematics

1 answer:

zimovet [89]2 years ago

6 0

Answer:d = √ ((X2-X1)2+(Y2-Y1)2)

d = √ (5--3)2+(5--4)2

d = √ ((8)2+(9)2)

d = √ (64+81)

d = √ 145

Xm=(X1+X2)/2

Xm=(-3+5)/2=1

Ym=(Y1+Y2)/2

Ym=(-4+5)/2=0.5

Slope = (Y2-Y1) = (5--4) = (9) = 1.125

(X2-X1) (5--3) (8)

The midpoint is: (1,0.5)

y = mx + b

y = 1.13x + b

-4 = 1.13×-3 + b

-4 = -3.38 + b

-4--3.38 = b

-0.63 = b

y= 1.13x-0.63

0= 1.13x-0.63

-1.13x= -0.63

x= -0.63/-1.13 = 0.56

y= 1.13×0-0.63

y= -0.63

Step-by-step explanation:

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2 years ago

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I think your question seems to be :-

Write the equation of the circle that has a center of (-7, 17) with a radius of √19

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${:\implies \quad \sf \{x-(-7)\}^{2}+(y-17)^{2}=(\sqrt{19})^{2}}$

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x=4.75

6×4.75=28.5

15×4.75-12=59.25

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28.5+59.25+92.25=180

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I think this is right. I hope that it was helpful:)

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