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3 years ago

Find the distance between the points: (-3, -4) and (5, 5)

Mathematics

1 answer:

zimovet [89]3 years ago

6 0

Answer:d = √ ((X2-X1)2+(Y2-Y1)2)

d = √ (5--3)2+(5--4)2

d = √ ((8)2+(9)2)

d = √ (64+81)

d = √ 145

Xm=(X1+X2)/2

Xm=(-3+5)/2=1

Ym=(Y1+Y2)/2

Ym=(-4+5)/2=0.5

Slope = (Y2-Y1) = (5--4) = (9) = 1.125

(X2-X1) (5--3) (8)

The midpoint is: (1,0.5)

y = mx + b

y = 1.13x + b

-4 = 1.13×-3 + b

-4 = -3.38 + b

-4--3.38 = b

-0.63 = b

y= 1.13x-0.63

0= 1.13x-0.63

-1.13x= -0.63

x= -0.63/-1.13 = 0.56

y= 1.13×0-0.63

y= -0.63

Step-by-step explanation:

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4 years ago

Read 2 more answers

Help me solve this please

Semenov [28]

$\huge\underline{ \underline{ \bf{Answer࿐} }}$

parallel sides measure :

10 ft -(a)
12 ft. -(b)

Area :

44 ft²

height (h) = x

___________________

$\boxed{Area = \frac{1}{2} \times (a + b) \times h}$

$\dfrac{1}{2} \times (10 + 12) \times x = 44$

$\dfrac{1}{2} \times 22 \times x = 44$

$11x = 44$

$\boxed{ 4 \: \: ft}$

Therefore, height of Trapezoid is 4 ft

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