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USPshnik [31]
3 years ago
14

Two gears are connected and are rotating simultaneously. The smaller gear has a radius of 2 inches, and the larger gear has a ra

dius of 7 inches.
Part 1: What is the angle measure, in degrees and rounded to the nearest tenth, through which the larger gear has rotated when the smaller gear has made one complete rotation?
Part 2: How many rotations will the smaller gear make during one complete rotation of the larger gear?
Show all work.
Mathematics
2 answers:
sleet_krkn [62]3 years ago
5 0

Answer:

Let r represent the radius of the smaller circle and R the radius of the larger circle.

Apply ratios: the radius of smaller circle to radius of larger circle, i.e.

r: R = 3 : 7.

I complete rotation = 360 degrees.

Part 1:

For one complete rotation of the smaller circle, the larger circle is rotated through: (3/7)*(360) = 154.3 degrees

Part 2:

For one complete rotation of the larger circle, the larger circle is rotated through: (7/3)*(360) = 840.0 degrees

This is equivalent to (840/360) = 2.3 rotations

Alternatively, use the ratios:

The number of rotations = R/r = 7/3 = 2.3 rotations  

BRAINLIEST PLEASE??

Step-by-step explanation:

Anika [276]3 years ago
3 0

Answer:

Step-by-step explanation:

for smaller gear circumference=2π×2=4π inches

for larger gear

l=4π

θ=l/r

θ=(4 ×180)/7=720/7=102 .9°

for larger gear circumference=2π×7=14π

number of rotations=(14π)/4π=7/2=3.5 rotations or 3 1/2 rotations.

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Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v
jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

<u>Step :-(i)</u>

Given  x = 1 6 (u + v)  …(i)

  Differentiating equation (i) partially with respective to 'u'

               \frac{∂x}{∂u} = 16(1)+16(0)=16

  Differentiating equation (i) partially with respective to 'v'

              \frac{∂x}{∂v} = 16(0)+16(1)=16

  Differentiating equation (i)  partially with respective to 'w'

               \frac{∂x}{∂w} = 0

Given  y = 1 6 (u − v) …(ii)

  Differentiating equation (ii) partially with respective to 'u'

               \frac{∂y}{∂u} = 16(1) - 16(0)=16

 Differentiating equation (ii) partially with respective to 'v'

               \frac{∂y}{∂v} = 16(0) - 16(1)= - 16

Differentiating equation (ii)  partially with respective to 'w'

               \frac{∂y}{∂w} = 0

Given   z = 6uvw   ..(iii)

Differentiating equation (iii) partially with respective to 'u'

               \frac{∂z}{∂u} = 6vw

Differentiating equation (iii) partially with respective to 'v'

               \frac{∂z}{∂v} =6 u (1)w=6uw

Differentiating equation (iii) partially with respective to 'w'

               \frac{∂z}{∂w} =6 uv(1)=6uv

<u>Step :-(ii)</u>

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

                                                         \left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|

   Determinant       16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

                                                                                 = -3072uv

<u>Final answer</u>:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

 

               

     

6 0
3 years ago
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240

Step-by-step explanation:

8 0
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Suppose you are given a cube made of magnesium (mg) metal of edge length 2.15 cm. (a) calculate the number of mg atoms in the cu
SVETLANKA909090 [29]

solution:

a) To calculate the volume of cube of edge 1.0cm

Volume= (edge)³

=(100cm) ³

= 1cm³

To find the mass of MG atoms  

Density = mass/volume

Mass of mg = 1.74g/cm³ x 1cm³

       = 1.74g

To find the number of mg atoms,

Molar mass of mg = 24.31g

24.31g mg contain 6.022 x 10²³ atoms of mg  

1.74g mg contain = 6.022 x 10²³mg atoms/24.31g mg x 1.74g mg

    = 0.4310 x 10²³mg atoms

    = 4.31 x 10²² mg atoms

B) to find the volume occupied by mg atoms  

    Total volume of cube = 1 cm³

    Volume occupied by mg atoms  

  = 74% of 1cm³

=74/100 x 1cm³= 0.74cm³

To find the volume of 1 mg atom  

4.31 x 10²² mg atoms occupy 0.74 cm³

1 atom will occupy 0.74cm³

1 atom will occupy = 0.74cm³/4.31 x 10²²mg atoms x 1mg atom

volume of 1 mg atom = 0.1716 x 10⁻²²cm²

Volume of 1 mg atom = 4/3 π³ in the form of sphere.

4/3πr³ = 0.1716 x 10⁻²²cm³

R³ = 0.1716 x 10⁻²²cm³x 4/3 x 7/22

R³ = 0.04095 x 10⁻²²cm³

R = 0.1599 x 10⁻⁷cm

1 = 10⁻¹⁰cm

 = 0.1599 x 10⁻⁷cm

 = 1pm/1 x 10⁻¹⁰cm  x 0.1599 x 10-7cm

= 1.599 x 10² pm  

R= 1.6 x 10²pm


3 0
3 years ago
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Answer:

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4 0
3 years ago
Circle assignment! THANKS so much its worth so much of my grade
kogti [31]

Answer:

1. B) Figure B.

2. C) Figure C.

3. D) Figure D.

4. C) Figure C.

Step-by-step explanation:

Given: Radius of Circle A= 4

           Radius of Circle B= 5

           Radius of circle C= 6

           Radius of circle D= 7

Now, finding circumference and area of all the circle.

We know, circumference of circle= 2\pi r

Area of circle= \pi r^{2}

Where, r= radius of circle and π = 3.14

First, solving for figure A

Circumference= 2\times 3.14\times 4= 25.12\ cm

Area= 3.14\times 4^{2} = 50.24\ cm^{2}

Solving for Figure B

Circumference= 2\times 3.14\times 6= 31.4\ cm

Area= 3.14\times 5^{2} = 78.5\ cm^{2}

Solving for Figure C

Circumference= 2\times 3.14\times 6= 37.68\ cm

Area= 3.14\times 6^{2} = 113.04\ cm^{2}

Solving for Figure D

Circumference= 2\times 3.14\times 7= 43.96\ cm

Area= 3.14\times 7^{2} = 153.86\ cm^{2}

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   3. Answer is Figure D

   4. Answer is Figure C.

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4 years ago
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